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adelina 88 [10]
2 years ago
6

If g is a differentiable function such that g(x)<0 for all real numbers x and if f'(x) = (x2 - 4)g(x), which of the following

is true? i. f has relative maxima at x-2 and at x-2.
ii. f has relative minima at x=-2 and at x=2.
iii. It cannot be determined if fhas any relative extrema.
iv. f has a relative maximum at x=-2 and a relative minimum at x=2.
v. f has a relative minimum at x=-2 and a relative maximum at x=2.
Mathematics
1 answer:
galina1969 [7]2 years ago
6 0

We want to see what can we say about f(x) extremes for the given information. We will see that the correct option is:

V: f has a relative minimum at x=-2 and a relative maximum at x=2.

<h3>Maximums and minimums.</h3>

A given function f(x) will have a maximum/minimum at x₀ if:

f'(x₀) = 0

  • It will be a maximum if f''(x₀) < 0
  • It will be a minimum if f''(x₀) > 0.

Here we do know that:

  • f'(x) = (x^2 - 4)*g(x)
  • g(x) < 0 for all numbers x.

Then the only zeros of f'(x) are when (x^2 - 4) = 0.

And this happens for x = 2 and x  = -2

Now let's see if these are minimums or maximums, we have:

f''(x) = 2*x*g(x) + (x^2 - 4)*g'(x)

If we evaluate this in x = 2, we get:

f''(2) = 2*2*g(2) + (2^2 - 4)*g'(2)

       = 4*g(2) + 0*g'(2) = 4*g(2)

And g(x) is always negative, then 4*g(2) < 0, then:

f''(2) < 0

Meaning that in x = 2 we have a relative maximum.

For x = -2 we have:

f''(-2) = 2*-2*g(-2) + ((-2)^2 - 4)*g'(-2)

       = -4*g(2) > 0

Then f''(-2) > 0, meaning that in x = -2 we have a relative minimum.

Then the correct option is:

V:  f has a relative minimum at x=-2 and a relative maximum at x=2.

If you want to learn more about maximums and minimums, you can read:

brainly.com/question/1938915

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find attached the C-chart(control chart)

Step-by-step explanation:

Sample Irregularities Sample Irregularity Sample Irregularity

1 18 6 11 11 10

2 14 7 4 12 16

3 6 8 10 13 5

4 14 9 12 14 15

5 8 10 9 15 17

Samples/Irre Cont'd

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17 - 15

18 - 9

19 - 15

20 - 17

Using these? data, set up a? c-chart with z =33.

UCLc =

LCLc =

     Sample irreg     mean(CL) UCL LCL

              ularities

1 18 10.8 25.77155197 -4.171551971

2 14 10.8 25.77155197 -4.171551971

3 6 10.8 25.77155197 -4.171551971

4 14 10.8 25.77155197 -4.171551971

5 8 10.8 25.77155197 -4.171551971

6 11 10.8 25.77155197 -4.171551971

7 4 10.8 25.77155197 -4.171551971

8 10 10.8 25.77155197 -4.171551971

9 12 10.8 25.77155197 -4.171551971

10 9 10.8 25.77155197 -4.171551971

11 11 10.8 25.77155197 -4.171551971

12 16 10.8 25.77155197 -4.171551971

13 5 10.8 25.77155197 -4.171551971

14 1 10.8 25.77155197 -4.171551971

15 17 10.8 25.77155197 -4.171551971

16 4 10.8 25.77155197 -4.171551971

17 15 10.8 25.77155197 -4.171551971

18 9 10.8 25.77155197 -4.171551971

19 15 10.8 25.77155197 -4.171551971

20 17 10.8 25.77155197 -4.171551971

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