Answer: c
Step-by-step explanation:
Answer:
vvvvvvvv
Step-by-step explanation:
A.36
B.5
C.1.70
D.7
E.3.80
F.100
G.14
H.0.64
I.1.02
J.9
Basically you dived the two numbers for your awnser
To calculate g, we use the formula F= mg. F is given as 180N, and m is given as 30 kg, therefore:
180N = (30kg)(g)
g = 6 m.s-1.
The motion of this object would be decreased on Earth as more force would be required to lift it. If we assume g is 9.8 m.s-1 on Earth, we can calculate the force required.
F = mg
= (30kg)(9.8 m.s-1)
= 294 N
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
It would be 20 hrs because if you put them both in an equation aka y=25x+100 and y=30x just plug in numbers into the x until they both have the answer which in this case is 20
