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Scilla [17]
3 years ago
10

What is the solution to this inequality?

Mathematics
1 answer:
gavmur [86]3 years ago
8 0

Answer:

x < -5 (the first option)

Step-by-step explanation:

I hope this helps!

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3 because 3•3 is 9 and 9•3 is 27
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Over what interval is the function in this graph increasing?
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C because -3 is less than 2 and we’ll stay the same
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HELP ME WITH THIS PLEASE!!! COORDINATES!
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(0, 4)
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For a 90 degrees clockwise rotation, the rule is (y, -x)
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What is the measure of &lt;R? ​
Verdich [7]

Answer:

<R=23°

Step-by-step explanation:

The sum of angles in a triangle is 180°

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4 years ago
Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)
lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

y + 3 = \frac{1}{2}(x-6)

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or y-y_1 = m (x-x_1) format. Remember that the number in place of the m is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction (-\frac{2}{1}), and flip its numerators and denominators. Therefore, the perpendicular slope would be \frac{1}{2}.

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, y-y_1 = m (x-x_1). In order to write an equation, the x_1, y_1, and m have to be substitute for with real values.

The m represents the slope. We already calculated that in the last step, so put \frac{1}{2} in place of the m. The x_1 and y_1 represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for x_1 and -3 for y_1:

y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)

Therefore, (again, assuming that the line can be put in point-slope form) the answer is y + 3 = \frac{1}{2}(x-6).

5 0
3 years ago
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