Answer: the new pressure will be 300mmHg
Explanation:
V1 = 30L.
V2 = 50L
P1 = 500mmHg
P2 =?
P1V1 = P2V2
30 x 500 = P2 x 50
P2 = (30 x 500) / 50
P2 = 300mmHg
The temperature : 263.016 K
<h3>Further explanation</h3>
Combined with Boyle's law and Gay Lussac's law
P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = gas end pressure
V2 = the final volume of gas
T1 = initial gas temperature (K)
T2 = gas end temperature
P1=760 mmHg
V1= 4 L
T1 = 275 K
P2=704 mmHg
V1=4.13 L
Answer:
35.0 kPa
Explanation:
As pressure decreases, the volume of a gas increases at a given temperature., so since the balloon got bigger, the new pressure must be less than 103kPa
Assuming the temperature does not change, use Boyles Law
P1V1 = P2V2
(103kPa) (1750L) = P2 (5150L)
P2 = (103)(1750) / 5150
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