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balandron [24]
3 years ago
13

Assume the average apple has a mass of 167 grams. How many apples are in a bag of apples that weighs 2000 grams? Enter your numb

er answer belowand round to the nearest whole number
Chemistry
1 answer:
forsale [732]3 years ago
4 0

Answer:

12

Explanation:

167x=2000

x=11.976

rounds to 12

You might be interested in
describe the number of protons, neutrons, and electrons in the atom, where each type of particle is located​
Sever21 [200]

Answer:

Protons - positive charge located in the nucleus

Neutrons - neutral charge located in the nucleus

Electrons - negative charge located outside the nucleus (they orbit)

6 0
3 years ago
n-Butane fuel (C4H10) is burned with the stoichiometric amount of air. Determine the mass fraction of each product. Also, calcul
tia_tia [17]

Answer:

  1. 0.1852
  2. 0.0947
  3. 0.7201
  4. 3.0345 kg CO_{2} / Kg C_{4} H_{10}
  5. 15.3848 Kg air / kg C_{4} H_{10}

Explanation:

Molar masses of each product are :

Butane = 58 kg /kmol

Oxygen = 32 kg/kmol

Nitrogen = 28 kg/kmol

water = 18 kg/kmol

<u><em>1) Calculate the mass fraction of carbon dioxide </em></u>

= ( 4 * 44 ) / ( (5 * 18) + (4 *44 )+ (24.44 * 28) )

= 176 / 950.32

= 0.1852

<em><u>2) Calculate the mass fraction of water </u></em>

= ( 5 * 18 ) /  (( 5* 18 ) + ( 4*44) + ( 24.44 * 28 ))

= 90 / 950.32

= 0.0947

<em><u>3) Calculate the mass fraction of Nitrogen </u></em>

= (24.44 * 28 ) / ((4 * 44 ) + ( 24.44 * 28 ) + ( 5 * 18 ))

= 684.32 / 950.32

= 0.7201

<em><u>4) Calculate the mass of Carbon dioxide in the products</u></em>

Mco2 = ( 4 * 44 ) / 58  = 3.0345 kg CO_{2} / Kg C_{4} H_{10}

<u>5) Mass of Air required per unit of fuel mass burned </u>

Mair = ( 6.5 * 32 + 24.44 *28 ) / 58  = 15.3848 Kg air / kg C_{4} H_{10}

5 0
3 years ago
What is the frequency of a particular type of electromagnetic
gizmo_the_mogwai [7]

Answer:

f = 0.6× 10¹⁶ Hz

Explanation:

Given data:

Wavelength of radiation = 5.00 × 10⁻⁸ m

Frequency of radiation = ?

Solution:

Formula:

Speed of light = wavelength × frequency

speed of light = 3 × 10⁸m/s

Now we will put he values in formula.

3 × 10⁸m/s = 5.00 × 10⁻⁸ m ×  f

f = 3 × 10⁸m/s / 5.00 × 10⁻⁸ m

f = 0.6× 10¹⁶ s⁻¹

s⁻¹ = Hz

f = 0.6× 10¹⁶ Hz

4 0
3 years ago
How does a purebred individual differ from a hybrid individual?
zimovet [89]
Im gonna go based on the content of their blood. So as the generation continues, a purebred's blood has not differentiated too much and contains 98-100% of a "pure" bloodline meaning no outsiders of where this purebred originated has mixed. A hybrid is where the original bloodline is mixed with many others, so while a purebred has 99% of the original bloodline and the hybrid has 50% and he other half belongs to an entirely different line.
5 0
3 years ago
What is the pressure of nitrogen in atmospheres of a sample that is at 516.0 mm hg?
Masteriza [31]

Answer:

nitrogen in atmospheres of a sample is 0.679

6 0
3 years ago
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