Answer:- work = 319 J
Solution:- The volume of the gas decreases from 5.35 L to 1.55 L.
= -3.80 L
external pressure is given as 0.829 atm.
where w is representing work.
Let's plug in the values and calculate pressure-volume work:
w = 3.15 atm.L
We need to convert atm.L to J.
1 atm.L = 101.325 J
So, 
= 319 J
So, 319 J of work is involved in a chemical reaction. Positive work means the work is done on the system.
True I believe because when the current circuit is at its limit it will be damaged
Answer:
Partial pressure of oxygen = 23.38 kpa (Approx)
Explanation:
Given:
Amount of oxygen = 23.15%
Amount of nitrogen = 76.85%
Pressure (missing) = 101 kpa
Find:
Partial pressure of oxygen
Computation:
Partial pressure of oxygen = [Amount of oxygen x Pressure]/100
Partial pressure of oxygen = [23.15% x 101]/100
Partial pressure of oxygen = 23.38 kpa (Approx)
Li + e- ===> Li+
it looses its valence electron to form a uni-positive ion
Answer:
It will cost $68,620.5 to the club to add the grass turf to their field.
Explanation:
length of the field = l = 0.102 km = 0.102 × 1000 m
( 1km = 1000 m)
Width of the field w = 0.069 km = 0.069 × 1000 m
Area of the field , A= l × w
Cost of grass turfing = 
Cost of grass turfing on field of 
:
It will cost $68,620.5 to the club to add the grass turf to their field.
