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julsineya [31]
2 years ago
15

What is the y-intercept of the graph that is shown below?

Mathematics
1 answer:
Law Incorporation [45]2 years ago
7 0

Answer:

y- intercept is (2;0)

Step-by-step explanation:

Then the x- intercept is (3;0)............

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Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting he
kondor19780726 [428]

Use the formula h(t) = -16t^2 + vt + s,

where t = time in air,

v = starting upward velocity,

s = the objects starting height.

from ground (s), the starting height is 0,

the ball's initial velocity (v) 25 feet per second

Solve:

v - 16t^2 + (25)t + 0

= -16t^2 + 25t. 0

Factor:

= -16t^2 + 25t

Find GCF:

0 = -16t^2 + 25t

Divide both sides by (t)

t(-16 + 25) = 0

t = 0; -16 + 25 = 0

Now Subtract 25 from both sides of equation:

-16 = -25

divide both sides by -16 to get -25/-16

= 1.56

Rounds to 1.60, or 1.6

Answer: 1.6 Seconds it will take for soccer ball to hit the ground again.

First part of the Equation: Answer: 9.8Ft. Soccer ball will reach at maximum height.

Hope that helps!!!! : )

6 0
3 years ago
A true-false examination was constructed with the answers running in the following sequence: T F F T F T F T T F T F F T F T F T
julia-pushkina [17]

Answer:

yes

Step-by-step explanation:

lets use a significance level of = 0.1

<u> Determine if the sequence indicates randomness </u>

First step :

H0 : pattern is random

H1 : pattern not random

n1 ( number of true answers ) = 10

n2 ( number of false answers ) = 10

also number of runs for T = 5

       number of runs for F = 5

Total number of runs = 5+ 5 = 10

Given that critical value at 0.05 = 23

we will reject the null hypothesis ( i.e the sequence departs from randomness )

3 0
2 years ago
Which expression is equivalent to b^-2/ab^-5?<br>a) a/b^5<br>b)1/ab^5<br>c)a^3b/1<br>d)b/a
Snezhnost [94]
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad&#10;\cfrac{1}{a^{-n}}\implies a^{{ n}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{b^{-2}}{ab^{-5}}\implies \cfrac{b^{-2}\cdot b^{+5}}{a}\implies \cfrac{b^{-2+5}}{a}\implies \cfrac{b^3}{a}
4 0
3 years ago
Please help please please
alexgriva [62]
Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}

The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go

{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers 

6/10
.6

If i'm wrong, sorry, haven't done this kind of stuff in a while
8 0
3 years ago
Melanie got a new employer pay job through the Jones recruitment agency the job pays $52,400 per year and the agency fee is equa
Zinaida [17]

Answer:

the  amount that pay to the agency is $1,091.67

Step-by-step explanation:

The computation of the amount that pay to the agency is as follows:

= Amount paid per year ÷ number of months × 25%

= $52,400 ÷ 12 months × 25%

= $1,091.67

Hence, the  amount that pay to the agency is $1,091.67

We simply applied the above formula so that the correct amount could come

5 0
2 years ago
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