Tyler moved 180 kilograms
30-12=18 so 18×2=36 36×5=180
Answer: C=[ (10) x (19.60)÷ (8)]
Step-by-step explanation:
Given , The cost of 8 books = $ 19.60
Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)
i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)
Now , cost of 10 books = (10) x (Cost of one book)
From (i) , we get
Cost of 10 books =$[ (10) x (19.60)÷ (8)]
Let C be the cost of 10 books ( in dollars) .
So , the equation would help determine the cost of 10 :
C=[ (10) x (19.60)÷ (8)]
Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
