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anastassius [24]

2 years ago

11

A spherical ball has a diameter of 8 inches. The ball has a slow leak in which the air escapes at the rate of 2.5 inches per sec

ond. How long would it take for the ball to deflate? Round to the nearest tenth.

1 answer:

s344n2d4d5 [400]2 years ago

4 0

Answer:

107.2 seconds

Step-by-step explanation:

Step one:

given

the diameter of ball 8 inches

radius= 8/2 = 4 in

The volume of the ball

$v=4/3 \pi r^3$

$v= 4/3*3.142*4^3\\\\v= 4/3*3.142*64\\\\v= 804.35/3\\\\v=268.12 in^3$

Step two:

we know that

rate= quantity/time

rate= 2.4 in per second

quantity= 268.12

time=?

time= quantity/rate

time= 268.12/2.5

time= 107.2 seconds

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What is an equation of the line that passes through the points (4,-5) and (-2,7)

Korvikt [17]

Answer:

y = -2x + 3

Step-by-step explanation:

y2 - y1/ x2 - x1

7 - (-5) / -2 - 4

-2

The slope is -2.

To find the y-intercept, you need to plug the coordinates into the equation.

y = -2x + b

7 = -2(-2) + b

7 = 4 + b

3 = b

y = -2x + 3

5 0

2 years ago

A shop sells three types of boots (football rugby and hiking). Sales are usually in the ration 6:2:3 Last month 24 pairs of boot

photoshop1234 [79]

Answer:

Total number of boots sold = 48 boots

Step-by-step explanation:

each pair of boot = 2 boots

total pairs of boots sold last month = 24 boots

Total number of boots sold = 48 boots

5 0

3 years ago

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[tex]cos {}^{4} α+sin {}^{4} α= \frac{1}{4} (3+cos4α)<br>Prove:<br>

asambeis [7]

Given:

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

To prove:

The given statement.

Proof:

We have,

$\cos^4 \alpha+\sin^4\alpha=\dfrac{1}{4}(3+\cos 4 \alpha)$

$LHS=\cos^4 \alpha+\sin^4\alpha$

$LHS=(\cos^2 \alpha)^2+(\sin^2 \alpha)^2$

$LHS=(\cos^2 \alpha+\sin^2\alpha)^2-2\sin ^2\alpha\cos^2 \alpha$ $[\because a^2+b^2=(a+b)^2-2ab]$

$LHS=(1)^2-2(1-\cos^2 \alpha)\cos^2 \alpha$ $[\because \cos^2 \alpha+\sin^2\alpha=1]$

$LHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

Now,

$RHS=\dfrac{1}{4}(3+\cos 4 \alpha)$

$RHS=\dfrac{1}{4}[3+(2\cos^2 2\alpha-1)]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2\cos^2 2\alpha]$

$RHS=\dfrac{1}{4}[2+2(2\cos^2 \alpha-1)^2]$ $[\because \cos 2\theta=2\cos^2\theta -1]$

$RHS=\dfrac{1}{4}[2+2(4\cos^4 \alpha-4\cos \alpha+1)]$ $[\because (a-b)^2=a^2-2ab+b^2]$

$RHS=\dfrac{1}{4}[2+8\cos^4 \alpha-8\cos \alpha+2]$

$RHS=\dfrac{1}{4}[4+8\cos^4 \alpha-8\cos \alpha]$

$RHS=1+2\cos^4 \alpha-2\cos \alpha$

$RHS=1-2\cos^2 \alpha+2\cos^4 \alpha$

$LHS=RHS$

Hence proved.

8 0

3 years ago

Shalnov [3]

The sum of the set of x - values given to us is calculated as; ∑X = -1

<h3>How to find the the sum of a set of data?</h3>

We are given;

X1 = 2, X2 = -8, X3 = 4, X4 = -8 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6

1) ∑X = X1 + X2 + X3 + X4

∑X = 2 + (-8) + 4 + 1 = -1

2) ∑Y = Y1 + Y2 + Y3 + Y4

∑Y = 3 + (-8) + 10 + 6

∑Y = -11

3) ∑ X² = X₁² + X₂² + X₃² + X₄²

∑X² = (2)² + (-8)² + (4)² + (1)²

∑X² = 85

4) ∑Y² = Y₁² + Y₂² + Y₃² + Y₄²

∑X² = (-3)² + (-8)² + (10)² + (6)²

∑X² = 209

Complete question is;

Two variables, X and Y assume the values X1 = 2, X2 = -5, X3 = 4, X4 = 1 and Y1 = -3, Y2 = -8, Y3 = 10, Y4 = 6, respectively. Calculate (a) ∑X, (b) ∑ Y, (c) ∑ X² (d) ∑ Y²

Read more about Sum of data at; brainly.com/question/15858152

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2 years ago

Identify the factors of 9x2 + 24x + 16.

lana [24]

Answer:

A

Step-by-step explanation:

12x+12x=+24x

24x is equal to the middle value

5 0

3 years ago

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