Question

A spherical ball has a diameter of 8 inches. The ball has a slow leak in which the air escapes at the rate of 2.5 inches per second. How long would it take for the ball to deflate? Round to the nearest tenth.

Answer 1

Answer:

107.2 seconds

Step-by-step explanation:

Step one:

given

the diameter of ball 8 inches

radius= 8/2 = 4 in

The volume of the ball

$v=4/3 \pi r^3$

$v= 4/3*3.142*4^3\\\\v= 4/3*3.142*64\\\\v= 804.35/3\\\\v=268.12 in^3$

Step two:

we know that

rate= quantity/time

rate= 2.4 in per second

quantity= 268.12

time=?

time= quantity/rate

time= 268.12/2.5

time= 107.2 seconds