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Maru [420]
2 years ago
6

Help meee I don't know what to do anymore--

Mathematics
1 answer:
balandron [24]2 years ago
5 0

Answer:

It is increasing by 40 and the first game will 40 the next is 80 the next is 120 and it keeps going on

Step-by-step explanation:

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A rectangular box with a square base is open at the top and has a volume of 12 cubic feet. Each side of the base has a length of
Stolb23 [73]

We know that the side lengths of the square base are: x * x. The volume is 12, so for now, let's say that y is the other side length. Then, x * x * y = 12. We can solve for y: y = 12/x^2. Now, we find the surface area of the 5 sides.

Four of the sides have the same area: x * (12/x^2) = 12/x, so we multiply this by 4: 48/x.

The last side is the base: x * x = x^2.

We add 48/x to x^2:

x^2 + 48/x

So, the answer is the fourth choice, (d).

4 0
3 years ago
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
Mr. Wilson's desk drawer contains 4 black, 3 blue, and 3 red pens. If he selects one pen a random, what is the probability that
gtnhenbr [62]
<h3>Answer:  3/5</h3>

Work Shown:

3 blue + 3 red = 6 pens that are either blue or red

4 black + 3 blue + 3 red = 10 pens total

6/10 = 3/5 is the probability of selecting either blue or red

3/5 = 0.60 = 60%

3 0
3 years ago
Solve for the following if x = 6: (Hint: substitute 6 for the letter x and work the problem. You will work more with substitutio
MrRa [10]
If x=6 it is
9. 5
10. 18
11. 23
12. 5.5
13.68
if x=3 it is
2
15
8
11
41
5 0
2 years ago
Read 2 more answers
There are20 keys on a keychain. One of the keys starts a car. If a key is randomly chosen what is the probability that it starts
pogonyaev
The answer is 5%........


7 0
3 years ago
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