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VashaNatasha [74]
2 years ago
15

Which product in the reaction forms a precipitate? KNO3 AgCl AgK no precipitate formed.

Chemistry
1 answer:
bija089 [108]2 years ago
7 0

The precipitate formed in the reaction has been AgCl. Hence, option B is correct.

The precipitate has been the solid insoluble substance that has been formed as the product in the double displacement reaction.

The precipitate settles down in the aqueous reaction mixture and are resulted from the double displacement reaction.

<h3>Which one  is the precipitate?</h3>

The reaction of silver nitrate and KCl has been:

\rm AgNO_3\;+\;KCl\;\rightarrow\;AgCl\;+\;KNO_3

The reactants in the reaction are in the aqueous form. Thus, silver nitrate and KCl are aqueous.

The potassium nitrate has been an aqueous solution, while the silver chloride has been the solid product that precipitates out.

\rm AgNO_3\;(aq)\;+\;KCl\;(aq)\rightarrow\;AgCl\;(\downarrow)+\;KNO_3\;(aq)

Thus, the precipitate formed in the reaction has been AgCl. Hence, option B is correct.

Learn more about precipitate, here:

brainly.com/question/5019199

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calculate the standard potential arising from the reaction in which NADH is oxidized to NAD and the corresponding biological sta
melisa1 [442]

Answer:

-219.99kJ

Explanation:

The acronym '' NADH'' simply stands for what is known as coenzyme 1 with full meaning of Nicotinamide Adenine Dinucleotide Hydride. This substance is useful in the production of energy. The oxidation reaction of NADH causes it to produce NADP⁺ and the oxygen produces water when it is in the reduction process. The balanced equation for the oxidation reaction is given below as:

NADPH ---------------------------------------------------------------------> NADP⁺H⁺ + 2e⁻.

Also, the balanced equation for the reduction reaction is given below as:

\frac{1}{2} O₂ + 2H⁺ + 2e⁻ --------------------------------------------------------------> H₂O.

It can be shown from the above REDOX reaction that the total number of electrons getting transferred is 2.

The  Gibbs energy = -nFE. where n = 2, F = faraday's constant = 96485.3329 C and E = overall cell potential.

The overall cell potential = E[ reduction reaction] - E[oxidation reaction] = 0.82 - (- 0.32 ) = 1.14 V.

Hence, the Gibbs energy = - 2 × 96485.3329 × 1.14 = -219.99kJ

7 0
3 years ago
Need helpppppp hurry pls, i just really need help
mojhsa [17]

Answer:

6.8 mole of O₂

Explanation:

Given expression:

       2H₂   +   O₂   →   2H₂O

Number of moles of H₂ = 13.6moles

Unknown:

Number of moles of O₂  = ?

Solution:

In the given problem, we are to find the number of moles of oxygen gas that will use up 13.6mole of hydrogen gas;

 From the reaction equation;

             2 mole of H₂ will completely react with 1 mole of O₂

         13.6 moles of H₂ will completely be used up by \frac{13.6}{2} mole of  O₂

                                                                                        = 6.8 mole of O₂

7 0
3 years ago
An FAS calibration curve (absorbance, y-axis vs. FAS in g/mL) gave an equation he regression line of: y-3678(x)+0.056. If an unk
mezya [45]

Answer:

FAS concentration = 1.61*10^-4M

Explanation:

Beer Lambert's law relates the absorbance (A) of a substance to its concentration (c) as:

A = \epsilon lc----(1)

where ε = molar absorption coefficient

l = path length

A plot of 'A' vs 'c' gives a straight line with slope = εl

In addition absorbance (A) is related to % Transmittance (%T) as:

A = 2-log%T----(2)

For the FAS solution, the corresponding calibration fit is given as:

y = 3678(x) + 0.056

This implies that the slope = εl = 3678

It is given that %T = 25.6%

A = 2-log(25.6)=0.592

Based on equation(1):

c = \frac{A}{\epsilon l}=\frac{0.592}{3678}=1.61*10^{-4}M

8 0
3 years ago
How many atoms will there be in 5.00 g of gold. (Use ^ to show the exponent in scientific notation. For example, 4 X 1011 should
gayaneshka [121]

Answer:

1.53x10^22 atoms of Au

Explanation:

To find the atoms of gold we need first, to convert the mass of gold to moles using molar mass of gold (196.97g/mol). Then, these moles must be converted to number of atoms based on definition of moles (1 mole = 6.022x10²³ atoms).

<em>Moles Au:</em>

5.00g Au * (1mol / 196.97g) = 0.0254 moles of Au

<em>Atoms of Au:</em>

0.0254 moles * (6.022x10²³ atoms / 1 mole) =

<h3>1.53x10^22 atoms of Au</h3>
3 0
3 years ago
In the formula 5CaSO4 the total number of sulfur atoms present is a. 1. b. 5. c. 9. d. 20?
podryga [215]
The answer is b . (1*5=5)
4 0
3 years ago
Read 2 more answers
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