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dlinn [17]
4 years ago
6

The liquid-phase reaction follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of

the A and B feed streams are 2 M before mixing. The volumetric flow rate of each stream is 5 dm3/min, and the entering temperature is 300 K. The streams are mixed immediately before entering. Two reactors are available. One is a gray, 200.0-dm^3 CSTR that can be heated to 77C or cooled to 0C, and the other is a white, 800.0-dm^3 PFR operated at 300 K that cannot be heated or cooled but can be painted red or black. Note that k = 0.07 dm^3 /mol/min at 300K and E =20 kcal/mol.
Required:
a. Which reactor and what conditions do you recommend? Explain the reason for your choice.
b. How long would it take to achieve 90% conversion in a 200-dm^3 batch reactor with after mixing at a temperature of 77C?
c. What would your answer to part (b) be if the reactor were cooled to 0C?
Chemistry
1 answer:
Vera_Pavlovna [14]4 years ago
5 0

e kajajdjae no squo viboes  we eso doadks Answer:ipao han meExplanation:no

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Answer:

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Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =
BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

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As we know that CaCO₃ dissociates to give Ca^{2+} ion and CO_3^{2-} ion.

The solubility equilibrium reaction will be:

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The expression for solubility constant for this reaction will be,

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Let solubility of CaCO₃ be, 's'

K_{sp}=(s)\times (s)

K_{sp}=s^2

8.7\times 10^{-9}=s^2

s=9.33\times 10^{-5}mol/L

Therefore, the solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

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