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cricket20 [7]
2 years ago
11

Julian has 1/2 pan of cranberry bars left from the picnic. His family eats 5/8 of the remaining cranberry bars for breakfast. Wh

at fraction of the whole pan of cranberry bars did Julian’s family eat?
Mathematics
1 answer:
irina1246 [14]2 years ago
7 0

The fraction of pan of cranberry bars did Julian’s family eat is 5/16

<h3>Fraction</h3>

  • Cranberry left = 1/2 pan

  • Quantity eaten by family = 5/8 of the remaining

Fraction of the whole pan of cranberry bars did Julian’s family eat = 5/8 of 1/2

= 5/8 × 1/2

= 5/16

Therefore, the fraction of pan of cranberry bars did Julian’s family eat is 5/16

Learn more about fraction:

brainly.com/question/11562149

#SPJ1

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Answer:

P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)

And we can find this probability using the complement rule and the normal standard distribution and we got:

P(z>6.302)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of attacks of a population, and for this case we know the distribution for X is given by:

X \sim N(510,14.28)  

Where \mu=510 and \sigma=14.28

We are interested on this probability

P(X>600)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)

And we can find this probability using the complement rule and the normal standard distribution and we got:

P(z>6.302)=1-P(z

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