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cricket20 [7]
1 year ago
11

Julian has 1/2 pan of cranberry bars left from the picnic. His family eats 5/8 of the remaining cranberry bars for breakfast. Wh

at fraction of the whole pan of cranberry bars did Julian’s family eat?
Mathematics
1 answer:
irina1246 [14]1 year ago
7 0

The fraction of pan of cranberry bars did Julian’s family eat is 5/16

<h3>Fraction</h3>

  • Cranberry left = 1/2 pan

  • Quantity eaten by family = 5/8 of the remaining

Fraction of the whole pan of cranberry bars did Julian’s family eat = 5/8 of 1/2

= 5/8 × 1/2

= 5/16

Therefore, the fraction of pan of cranberry bars did Julian’s family eat is 5/16

Learn more about fraction:

brainly.com/question/11562149

#SPJ1

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The answer should be B. to the nearest 25 ML
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Solve the system of equations -x+ 2y = –11 and 5x – 8y = 39 by<br> combining the equations.
Alchen [17]

Answer:

x=-5, y=-8. (-5, -8).

Step-by-step explanation:

-x+2y=-11

5x-8y=39

---------------

5(-x+2y)=5(-11)

5x-8y=39

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-5x+10y=-55

5x-8y=39

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2y=-16

y=-16/2

y=-8

-x+2(-8)=-11

-x-16=-11

-x=-11+16

-x=5

x=-5

3 0
2 years ago
Which equation shows an example of the associative property of addition? (–7 i) 7i = –7 (i 7i) (–7 i) 7i = 7i (–7i i) 7i × (–7i
mr Goodwill [35]

The equation which shows the associative property of addition is; (–7 + i) +7i = –7 (i +7i).

<h3>What is the associative property of addition?</h3>

Associative property of addition postulates that Changing the grouping of addends does not change the sum of the numbers. As an instance, ( 5 + 3 ) + 4 = 5 + ( 3 + 4 )

Consequently, the equation which shows the associative property of addition is; (–7 + i) +7i = –7 (i +7i)

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5 0
2 years ago
Sean has some candy bars that he wants to give away. He is going to give each person \dfrac18 8 1 ​ start fraction, 1, divided b
Afina-wow [57]

Answer:

22 people

Step-by-step explanation:

Sean has 2 3/4 candy bars. That is 11/4 candy bars.

He wants to give out 1/8 candy bars.

The number of people that will get candy is:

\frac{11}{4} / \frac{1}{8}\\ \\= \frac{\frac{11}{4} }{\frac{1}{8}} \\\\\frac{11}{4} * \frac{8}{1} \\\\22

22 people can get candy.

8 0
3 years ago
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You are constructing a cardboard box from a piece of cardboard with the dimensions 2 m by 4 m. You then cut equal-size squares f
postnew [5]

Answer:

Dimensions:

l =3,15 m

w=1,15 m

x= 0,42 m   (height)

V(max) = 1,52 m³

Step-by-step explanation:

The cardboard is L = 4 m   and   W = 2 m

Let call x the length of the square to cut in each corner, then, volume of open box is:

For the side L       is  L - 2*x               l =  4 - 2*x

For the side W      is  W - 2*x             w=  2 - 2*x

The height              is  x

Volume of the open box, as function of x is:

V(x) = ( 4 -2x) * ( 2 - 2x) *x    ⇒  V(x) = ( 8 - 8x -4x + 4x²) *x

V(x) = ( 8 -12x + 4x² )*x     V(x) = 8x - 12x² + 4x³

V(x) = 8x - 12x² + 4x³

Taking derivatives on both sides of the equation

V´(x) = 8 - 24x + 12x²

V´(x) = 0       8  - 24x + 12x² = 0     reordering    12x² - 24x + 8  = 0

or    3x² - 6x + 2 = 0

A second degree equation. Solving for x

x₁,₂  = ( 6 ± √36 - 24 ) /6

x₁,₂  = ( 6 ± 3.46) /6

x₁  =  6 + 3,46 /6     x₁  = 1.58  we dismiss such solution because 1,58 * 2 = 3,15 and is bigger than 2 one of the side of the cardboard

x₂  =( 6 - 3,46 ) / 6

x₂  = 0,42 m

Dimensions of the open box

l  = 4 - 2*x     l  = 4 - 0,85      l  =  3,15 m

w = 2 -2*x    w  = 2 - 0,85     w = 1,15 m

x = 0,42 m

V(max) =3,15*1,15*0,42

V(max) = 1,52 m³

8 0
2 years ago
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