The formulas in question are
sin²(x) = (1 - cos(2x))/2
cos²(x) = (1 + cos(2x))/2
Then
sin⁴(4x) = (sin²(x))²
… = ((1 - cos(2x))/2)²
… = (1 - 2 cos(2x) + cos²(2x))/4
… = (1 - 2 cos(2x) + (1 + cos(4x))/2)/4
… = 1/4 - 1/2 cos(2x) + (1 + cos(4x))/8
… = 3/8 - 1/2 cos(2x) + 1/8 cos(4x)
Answer:
C. The bottom answer.
Step-by-step explanation:
the x intercepts are -1 and 1 (where y = 0)
the y intercept is 1 (where x = 0)
Answer: 56
Answer: What is the question theres not enough info