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musickatia [10]
4 years ago
10

Mary bought 1 1/2kg of apples and Nancy bought 3 5/6 kg. How many kg did they buy all together.

Mathematics
1 answer:
siniylev [52]4 years ago
4 0
They both bought 5 1/3 kg of apples because 1 1/2 + 3 5/6= 5 1/3 kg
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erastovalidia [21]
Formula: total = principal x (1 + (interest rate x loan time))

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total = $1110
8 0
4 years ago
Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
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GenaCL600 [577]

A = (2 , 8 )

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therefore, midpoint of AB

( x1 + x2/2 , y1 + y2/2 )

→ ( 2 + 7/2 , 8 + (-5)/2 )

→ 9/2 , 3/2

→ 4.5 , 1.5

<em>so,</em><em> </em><em>option </em><em>B </em><em>is </em><em>correct</em>

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u> take</u></em><em><u> </u></em><em><u>care!</u></em>

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3 years ago
Expression 3 + y and 2 (6+y) are equivalent?
Assoli18 [71]

Answer:

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Step-by-step explanation:

I mean they aren't equivalent because if you do PEMDAS (parenthesis, exponents, multiply, divide, add, subtract) Then, you would do 2 times 6 because parenthesis, that equals 12 so the answer would be

3+y and 12+2y

6 0
3 years ago
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galben [10]

Answer: 3√-20 = 3√20√-1 = (3√20)i


Step-by-step explanation:

√-20 can be written √20√-1 since

(√20√-1)^2 is indeed -20.

3 0
3 years ago
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