Answer: ![DE\approx6.0](https://tex.z-dn.net/?f=DE%5Capprox6.0)
Step-by-step explanation:
Observe in the figure given in the exercise that four right triangles are formed.
In this case you can use the following Trigonometric Identity to solve this exercise:
From the figure you can identify that:
![\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE](https://tex.z-dn.net/?f=%5Calpha%20%3D53%5C%C2%B0%5C%5C%5C%5Chypotenuse%3D10%5C%5C%5C%5Cadjacent%3DBE%3DDE)
Then, you can substitute values:
![cos(53\°)=\frac{DE}{10}](https://tex.z-dn.net/?f=cos%2853%5C%C2%B0%29%3D%5Cfrac%7BDE%7D%7B10%7D)
The next step is to solve for DE in order to find its value. This is:
![10*cos(53\°)=DE\\\\DE=6.01](https://tex.z-dn.net/?f=10%2Acos%2853%5C%C2%B0%29%3DDE%5C%5C%5C%5CDE%3D6.01)
Finally, rounding the result to the nearest tenth, you get that this is:
![DE\approx6.0](https://tex.z-dn.net/?f=DE%5Capprox6.0)
Answer:
Omg i have that same question on a math test
Step-by-step explanation:
Answer:
An elephant
Step-by-step explanation:
2.86 tons is the weight of an elephant.
Answer: F (cos(230)).
Explanation:
Cosine corresponds to the x coordinate of points on a circle when the radius is drawn in like this, so the answer would be the cos of that angle, but you have to account for the fact that the 50 degree angle marked is just the reference angle not the entire angle so you have to add 180 degrees to that to get 230.
Answer:
The standard form of the equation for the conic section represented by
is:
![4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2](https://tex.z-dn.net/?f=4%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%5Cright%29%5Cleft%28y-12%5Cright%29%3D%5Cleft%28x-%5Cleft%28-5%5Cright%29%5Cright%29%5E2)
Step-by-step explanation:
We know that:
is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.
Given the equation
![x^2\:+\:10x\:+\:6y\:=\:47](https://tex.z-dn.net/?f=x%5E2%5C%3A%2B%5C%3A10x%5C%3A%2B%5C%3A6y%5C%3A%3D%5C%3A47)
Rewriting the equation in the standard form
![4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2](https://tex.z-dn.net/?f=4%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%5Cright%29%5Cleft%28y-12%5Cright%29%3D%5Cleft%28x-%5Cleft%28-5%5Cright%29%5Cright%29%5E2)
Thus,
The vertex (h, k) = (-5, 12)
Please also check the attached graph.
Therefore, the standard form of the equation for the conic section represented by
is:
![4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2](https://tex.z-dn.net/?f=4%5Cleft%28-%5Cfrac%7B3%7D%7B2%7D%5Cright%29%5Cleft%28y-12%5Cright%29%3D%5Cleft%28x-%5Cleft%28-5%5Cright%29%5Cright%29%5E2)
where
vertex (h, k) = (-5, 12)