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Hatshy [7]
3 years ago
13

When dolphin swims close to its prey, it transmits sound waves to figure out details (like direction where the fish is moving) o

f its prey. Now, if the frequency of the reflected waves has increased, would the dolphin catch up its prey or fall behind? Explain your answer.
Physics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

The frequency of the waves depends on the distance between wave fronts - considering a front as a maximum disturbance of the wave

(Consider the waves emitted by an organ pipe: condensation and rarefactions)

The waves themselves are a fixed distance apart -

as one moves towards the source the waves received will be closer together (higher frequency)

So if the frequency received increases, the distance between the source and the observer must be decreasing

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A 2 kg object is traveling in a circular path. What is the centripetal acceleration and centripetal force if the radius of the p
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Answer:

a = v²/R = 10²/6 = 16.7 m/s²

F = mv²/R = 2(16.7) = 33.3 N

Explanation:

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1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car e
tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 m/s^{2}

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

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Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5m/s^{2}

6 0
3 years ago
What is an example of frequency
emmasim [6.3K]

'Frequency' is a word that often confuses some people ... for no good reason.
It just means "frequent-ness" or "often-ness" ... how often something happens.

The SI unit of frequency is the Hertz (Hz).  Hz means 'per second'.
So  " 13 Hz "  means  13 per second.

Here are examples of frequency:

-- 780 kilohertz (on your AM radio dial)
-- 98.7 Megahertz (on your FM dial)
-- 5.8 Gigahertz
-- twice a day
-- three per week
-- every 6 months

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<span>its hard to turn cooked pancakes back into batter</span>
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Look at the picture for the answer

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