Answer:
According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D, the object is moving in the negative direction (i.e., has a negative velocity) and is speeding up.
Explanation:
<h3><u>Answer</u>;</h3>
A) the resting position of the wave
<h3><u>Explanation</u>;</h3>
- A wave is a transmission of a disturbance from one point which is the source to another, and this involves transfer of energy through a material medium.
- <em><u>Equilibrium refers to a state of balance between opposing forces, it is a state of balance in which opposing forces cancel one another. </u></em>
- <em><u>When wave is in rest position its called equilibrium position of a wave. When a wave travels through a material medium, the particles in the medium are disturbed from their resting, or equilibrium positions.</u></em>
Answer:
Final velocity, v = 25.3 m/s
Explanation:
Initial velocity of a locomotive, u = 19 m/s
Acceleration of the locomotive, a = 0.8 m/s²
Length of station, d = 175 m
We need to find its final velocity (v) when the nose leaves the station. It can be calculated using the third law of motion :
![v^2-u^2=2ad](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2ad)
![v^2=2ad+u^2](https://tex.z-dn.net/?f=v%5E2%3D2ad%2Bu%5E2)
![v^2=2\times 0.8\ m/s^2\times 175\ m+(19\ m/s)^2](https://tex.z-dn.net/?f=v%5E2%3D2%5Ctimes%200.8%5C%20m%2Fs%5E2%5Ctimes%20175%5C%20m%2B%2819%5C%20m%2Fs%29%5E2)
![v^2=(641)\ m^2](https://tex.z-dn.net/?f=v%5E2%3D%28641%29%5C%20m%5E2)
v = 25.31 m/s
v = 25.3 m/s
When the nose leaves the station, it will move with a velocity of 25.3 m/s. Hence, this is the required solution.
Answer:
Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.
Explanation:
Answer:
b) ![v=311.04 \,m.s^{-1}](https://tex.z-dn.net/?f=v%3D311.04%20%5C%2Cm.s%5E%7B-1%7D)
c) ![s=241864704\,m](https://tex.z-dn.net/?f=s%3D241864704%5C%2Cm)
Explanation:
Given:
Force, ![F=0.1 \,N](https://tex.z-dn.net/?f=F%3D0.1%20%5C%2CN)
mass, ![m=500\,kg](https://tex.z-dn.net/?f=m%3D500%5C%2Ckg)
acceleration, ![a=2\times 10^{-4} \,m.s^{-2}](https://tex.z-dn.net/?f=a%3D2%5Ctimes%2010%5E%7B-4%7D%20%5C%2Cm.s%5E%7B-2%7D)
initial velocity, ![u=0\,m.s^{-1}](https://tex.z-dn.net/?f=u%3D0%5C%2Cm.s%5E%7B-1%7D)
time, ![t=18\,days=(18\times 24\times 60\times 60)\,s](https://tex.z-dn.net/?f=t%3D18%5C%2Cdays%3D%2818%5Ctimes%2024%5Ctimes%2060%5Ctimes%2060%29%5C%2Cs)
(b)
Speed of the boat after 18 days:
![v=u+a.t](https://tex.z-dn.net/?f=v%3Du%2Ba.t)
![v=0+2\times 10^{-4} \times (18\times 24\times 60\times 60)](https://tex.z-dn.net/?f=v%3D0%2B2%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%20%2818%5Ctimes%2024%5Ctimes%2060%5Ctimes%2060%29)
![v=311.04 \,m.s^{-1}](https://tex.z-dn.net/?f=v%3D311.04%20%5C%2Cm.s%5E%7B-1%7D)
(c)
Distance traveled in 18 days:
using the equation of motion
![v^2=u^2+2a.s](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2a.s)
![311.04^2=0^2+2\times 2\times 10^{-4}\times s](https://tex.z-dn.net/?f=311.04%5E2%3D0%5E2%2B2%5Ctimes%202%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20s)
![s=241864704\,m](https://tex.z-dn.net/?f=s%3D241864704%5C%2Cm)