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Mademuasel [1]
4 years ago
6

A ball is fired at an angle of 45 degrees, the angle that yields the maximum range in the absence of air resistance. What is the

ratio of the ball's maximum height to its range?

Physics
2 answers:
Nesterboy [21]4 years ago
7 0
Look at the picture for the answer

OleMash [197]4 years ago
5 0

Answer: 0.361:1

Explanation:

Since Range is U^2sin2Φ/g

And maximum height = U^2 sin^2Φ/2g

For range sinceΦ= 45

Range = U^2sin90/g

Sin90=1

Range= U^2/g

For maximum height

U^2sin^2Φ/2g

U^2sin(45)^2/2g

0.723U^2/2g

Ratio of maximum height to range

0.723U^2/2g*g/U^2

0.723/2

0.361

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Answer:

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Now, plug in the values given and solve for 'W'. This gives,

W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J

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