A ball is fired at an angle of 45 degrees, the angle that yields the maximum range in the absence of air resistance. What is the ratio of the ball's maximum height to its range?
2 answers:
Look at the picture for the answer
Answer: 0.361:1
Explanation:
Since Range is U^2sin2Φ/g
And maximum height = U^2 sin^2Φ/2g
For range sinceΦ= 45
Range = U^2sin90/g
Sin90=1
Range= U^2/g
For maximum height
U^2sin^2Φ/2g
U^2sin(45)^2/2g
0.723U^2/2g
Ratio of maximum height to range
0.723U^2/2g*g/U^2
0.723/2
0.361
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