To solve this problem we will begin by applying the given relations of density in terms of mass and volume, and from this last value we will take its geometric measurement for a sphere (Approximation of a planet) From there we will find the radius of the planet. Finally we will make a comparison between the radius of the new planet and the radius of the earth to understand its proportion.
Defining the Volume variables we have to
Here
V= Volume
m = mass
=Density
For a spherical object the Volume is
PART A)
Equation we have
In this case the mass of new planet is 5.5times the mass of Earth,
Then,
The mass of the Earth is kg and the density is ,
Replacing we have that,
Therefore the radius of this new planet is
PART B) The value of radius of the Earth is
Then the relation between them is
Therefore the radius of the new planet in terms of radius of the Earth is
Answer:
Explanation:
Hello,
In this case, since we compute the required energy via:
Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:
Therefore, the energy turns out:
Best regards.
Answer:
20.1 m/s
Explanation:
Since You are later than usual getting to the stop and see the shuttle pulling away from the stop while you are still 3.9 m behind the bus stop. And In 40.9 m you will reach a barrier and you must catch the shuttle before that point.
Given that the shuttle has a constant acceleration of 4.5 m/s2.
The total distance to cover is:
Total distance = 40.9 + 3.9 = 44.8 m
Assuming you are starting from rest. Then initial velocity U = 0
Using the 3rd equation of motion to calculate the minimum velocity.
V^2 = U^2 + 2as
V^2 = 0 + 2 × 4.5 × 44.8
V^2 = 403.2
V = sqrt (403.2)
V = 20.1 m/s
Therefore, the minimum velocity you have to run at to catch the bus before it reaches the barrier is 20.1 m/s
You need to have the Mass and velocity