Answer:
Could you possible elaborate on the question more?
<span>T1 = 20.0 + 273 = 293.0 K
T2 = 8.00 + 273 = 281.0 K
use the combined gas law
p1V1/T1 = p2V2/T2
765 x 580/ 293.0 = 440 V2/ 281-0
V2 = 967 mL</span>
Moment of inertia for one rod is expressed as:
<span>
I(1)= I(end) + md^2 = (1\12)mL^2+m(L/2√2)^2=(5/24)mL^2
</span><span>
Therefore, for two rods:
</span><span>
I2 = 2I1 = (5/12)mL^2
</span><span>
For the moment of inertia at the pivot point,
</span><span>
I=I2+2md^2=(5/12)mL^2+2(m(L/2√2)^2)=(2/3)mL^2
</span><span>
Substituting the equations above to the equation for frequency:
</span><span>
f=(1/2π)√(2mgd/I)=(1/4π)√(6g/√2L)</span>
The waves are formed using inferred to contrast it
