The force exerted on the board by the karate master given the data is -4500 N
<h3>Data obtained from the question </h3>
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 1 m/s
- Time (t) = 0.002 s
- Mass (m) = 1 Kg
- Force (F) = ?
<h3>How to determine the force</h3>
The force exerted can be obtained as illustrated below:
F = m(v - u) / t
F = 1 (1 - 10) / 0.002
F = (1 × -9) / 0.002
F = -4500 N
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We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
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Answer:
The capacitance of the deflecting plates is 
.
Explanation:
The expression for the capacitance of the capacitor in terms of area and distance is as follows;
Here, C is the capacitance, A is the area, d is the distance and 
is the absolute permittivity.
Convert the side of the square from cm to m.
s= 3.0 cm
s= 0.030 m
Calculate the area of the square.
Put s= 0.030 m.
Convert distance from mm to m.
d= 5.0 mm
Calculate the capacitance of the deflecting plates.
Put , and 
.
Therefore, the capacitance of the deflecting plates is .
