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xxTIMURxx [149]
3 years ago
7

Plz simplify with steps

Mathematics
2 answers:
Pavel [41]3 years ago
7 0

Answer:

Hey There!

Let's solve...

\frac{a^{3} {b}^{5}  }{ {b}^{4} {a}^{6}  } +   \frac{ {a}^{8} {b}^{6}  }{ {b}^{7} {a}^{9}  } \\  \\  \\  =   \frac{ {a}^{3} { \cancel{b}^{5}} }{{  \cancel{b}^{4}} {a}^{6}  } \\  \\  =  \frac{ {a}^{3}b }{ {a}^{6} } \\  \\  =   \frac{ { \cancel{a}^{3}}b }{  \cancel{{a}^{6}} } \\  =  {a}^{6 - 3} =  {a}^{3}   \\  =  \frac{b}{ {a}^{3} }

Now

\frac{ {a}^{8} {b}^{6}  }{ {b}^{7} {a}^{9}  } \\  \\  \frac{ {a}^{8} }{ {a}^{9} } =  \frac{1}{a} \\  \\ so \: it \: is \:  \frac{ {b}^{6} }{ {b}^{7}a}  \\  \\  \frac{ {b}^{6} }{{b}^{7}  } =  \frac{1}{ba}

So now just make a fraction of them by adding + symbol...

So it will be

\frac{ {b} }{ {a}^{3} } +  \frac{1}{ba} \\  \\

<h2>I hope it is helpful to you...</h2><h3>Cheers!_____________</h3>
vivado [14]3 years ago
3 0

a³b⁵ / b⁴a⁶  ÷ a⁸b⁶ / b⁷a⁹  = 1 / a²

<h3>Indices:</h3>

Indices in math talk about a number raise to another or a variable. They are called exponents.

a³b⁵ / b⁴a⁶  ÷ a⁸b⁶ / b⁷a⁹

Using the law of indices we will simplify the expression as follows;

  • a³b⁵ / b⁴a⁶ =  a³⁻⁶ / b⁵⁻⁴ = a⁻³ / b = 1 / a³b
  • a⁸b⁶ / b⁷a⁹ = a⁸⁻⁹ / b⁶⁻⁷ = a⁻¹ /  b⁻¹ = 1 / ab

Therefore, let's combine the individual simplification.

1 / a³b  ÷ 1 / ab = 1 / a³b × ab / 1

1 / a³b × ab / 1 = 1 / a²

learn more on simplifying indices here: brainly.com/question/10584859?referrer=searchResults

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Step-by-step explanation:

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A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

\frac{dh}{dt} =-\frac{1}{3} --- rate of the height

r = 2

h = \frac{1}{3}

Required

Determine the rate of change of the cone volume

The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0
3 years ago
Using the method of completing the square, put each circle into the form
tatiyna

Answer:

Standard form: (x-\frac{1}{2})^2 + (y-0)^2 = 15

Center: (\frac{1}{2}, 0)

Radius: r =\sqrt{15}

Step-by-step explanation:

The equation of a circle in the standard form is

(x-h)^{2} + (y-k)^{2} = r^{2}

Where the point (h, k) is the center of the circle

To transform this equation 4x^{2} -4x + 4y^{2} - 59 = 0 this equation  in the standard form we use the method of square.

First, we group similar variables

(4x^{2} -4x) + (4y^{2}) - 59 = 0

Divide both sides of equality by 4

(x^{2} -x) + (y^{2}) - 14.75 = 0

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2=  (-\frac{1}{2})^2 = \frac{1}{4}

Now add (\frac{b}{2})^2 on both sides of the equality

(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})

Factor the expression and simplify the independent terms

(x-\frac{1}{2})^2 + (y^{2}) = 15

(x-\frac{1}{2})^2 + (y-0)^2 = 15

Then

h =\frac{1}{2}\\\\k=0

and the center is (\frac{1}{2}, 0)

radius r =\sqrt{15}

3 0
3 years ago
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