Answer:
<em>We can't find a unique price for an apple and an orange.</em>
Step-by-step explanation:
Suppose, the price of an apple is
and the price of an orange is 
They need $10 for 4 apples and 4 oranges. So, the first equation will be.......

They also need $15 for 6 apples and 6 oranges. So, the second equation will be........

Dividing equation (1) by 2 on both sides : 
Dividing equation (2) by 3 on both sides : 
So, we can see that both equation (1) and (2) are actually same. That means, we will not get any unique solution for
and
here. Both
and
have <u>"infinitely many solutions"</u>.
Thus, we can't find a unique price for an apple and an orange.
Answer: D
Step-by-step explanation:
dim A=(a,b), dim B=(c,d), in order to multiply, c=b
1) dim A=(1,2) , dim B=(1,2) but 2≠1
2) dim A=(2,1) , dim B=(2,2) but 1≠2
3) dim A=(2,2) , dim B=(1,2) but 2≠1
4) dim A=(2,1) , dim B=(1,2) 1=1: result (2,2)
we are given
slope is

y-intercept is (0,-3)

now, we can use slope intercept form of equation

where
m is slope
b is y-intercept
now, we can plug these values
we get

now, we have to write it in
Ax+By =C form
so, we will multiply both sides of equation by 3


Subtract both sides by 2x



so,
Answer is 
Don't be shy about using actual parentheses and commas.
Line through (1,8) perpendicular to

The perpendicular family is gotten by swapping the coefficients on x and y, negating exactly one of them. The constant is given directly by the point we're through:

Let's clear the fractions by multiplying both sides by 20.

Might as well stop here.
Answer: 25 x + 16 y = 153