Answer:
so am i ._. 15 not 1 ofc lol
Explanation:
Answer: 0m/s²
Explanation:
Since the forces acting along the plane are frictional force(Ff) and moving force(Fm), we will take the sum of the forces along the plane
According newton's law of motion
Summation of forces along the plane = mass × acceleration
Frictional force is always acting upwards the plane since the body will always tends to slide downwards on an inclined plane and the moving acts down the plane
Ff = nR where
n is coefficient of friction = tan(theta)
R is normal reaction = Wcos(theta)
Fm = Wsin(theta)
Substituting in the formula of newton's first law we have;
Fm-Ff = ma
Wsin(theta) - nR = ma
Wsin(theta) - n(Wcos(theta)) = ma... 1
Given
W = 562N, theta = 30°, n = tan30°, m = 56.2kg
Substituting in eqn 1,
562sin30° - tan30°(562cos30°) = 56.2a
281 - 281 = 56.2a
0 = 56.2a
a = 0m/s²
This shows that the trunk is not accelerating
Answer:
There's a video called Drawing Position vs Time Graphs made by MrDGenova that may help you, it's only three minutes long.
Explanation:
Hope that helps, if not, you could tell me what you don't understand and I could try explaining it in further detail.
Answer:
It's centripetal acceleration is 301.7 m/s²
Explanation:
The formula to be used here is that of the centripetal acceleration which is
ac = rω²
where ac is the centripetal acceleration = ?
ω is the angular velocity = 3 revolutions per second is to be converted to radian per second: 3 × 2π = 3 × 2 × 3.14 = 18.84 rad/s
r is the radius = 0.85 m
ac = 0.85 × 18.84²
ac = 301.7 m/s²
It's centripetal acceleration is 301.7 m/s²
Answer:
The net force is 500N downwards
Explanation:
When Haley is trying to pull an object upward. The below forces are acting on the object.
Fp = 5500N
Fg = 6000N
because the force of gravity is more than the force of the pull.
Fnet = Fg - Fp = 6000N - 5500N = 500N
And, the direction of the resultant force is the direction of the larger force.
