A. True
if cold air is replacing warm air it is a cold front and vice versa.
Answer:
10°C
Explanation:
To convert °F to °C, we use the formula:
°C = (°F - 32) * ( 5/9)
So, to convert 50°F to the equivalent in °C, we can proceed as follows:
°C = ( 50 - 32 ) * (5/9)
°C = ( 18 ) * (5/9), which is, approximately,
°C = 9.999999999... ≈ 10 (5/9 ≈0.555555...)
So, 50°F is equivalent to 10°C.
A) To calculate the charge of each coin, we must apply the expression of the Coulomb's Law:
F=K(q1xq2)/r²
F: The magnitud of the force between the charges. (F=2.0 N).
K: Constant of proporcionality of the Coulomb's Law (K=9x10^9 Nxm²/C²).
q1 and q2: Electrical charges.
r: The distance between the charges (r=1.35 m).
We have the values of F, K and r, so we can calculate q1xq2, because both<span> coins have identical charges:
</span>
q1xq2=(r²xF)/K
q1xq2=(1.35 m)²(2.0 N)/9x10^9 Nxm²/C²
q1xq2=3x10^-10 C
q1=q2=(<span>3x10^-10 C)/2
</span>Then, the charge of each coin, is:
<span>
q1=1.5x</span><span>10^-10 C
</span>q2=1.5x10^-10 C
B) <span>Would the force be classified as a force of attraction or repulsion?
</span>
It is a force of repulsion, because both coins have identical charges and both are postive. In others words, when two bodies have identical charges (positive charges or negative charges), the force is of repulsion.
1 mol of oxygen molecules = 2 * 16 = 32 grams.
x mol of oxygen = 16 grams
1/x = 32/16 Cross multiply
16 = 32x Divide by 32
16/32 = x
x = 1/2 mol
1 mol of anything has 6.02 * 10^23 somethings (molecules in this case).
1/2 mol = 6.02 *10^23 / 2
1/2 mol = 3.01 * 10^23 molecules <<<< answer
