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sweet [91]
3 years ago
14

50 points!

Physics
1 answer:
Tanya [424]3 years ago
5 0
From Kepler's 3rd law, time period of satellite orbiting around planet in a circular orbit is given by,
T² = 4π²r³/GM 
M= mass of the Earth = 6×10²⁴ Kg. 
∴ T² = 4×3.14²×(2.56×10⁷)³/6.67×10⁻¹¹×6×10²⁴ 
   T² = 1653339719
∴ T = 40661.28 seconds.
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(edited)
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Explanation:

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