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2 years ago

In the art club, there are 2 seventh graders for every 3 eighth graders. At

Mathematics

1 answer:

ahrayia [7]2 years ago

5 0

Answer:

Step-by-step explanation:

2/3 does not equal 7/12.

there would need to be 8 paintings by seventh graders for every 12 by eighth graders in order to have an equivalent ratio.

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Anna is making a banner out of 4 congruent triangles as shown below. How much blue trim will she need for each side

Ede4ka [16]

Answer:

The length of each blue trim is 17.2 inches

Step-by-step explanation:

Given

See attachment for banner

Required

The length of each blue trim

Since all 4 triangles are equal, then the dimension of 1 triangle is:

$Side\ 1 = 10$

$Side\ 2 = 14$

The hypotenuse (x) of the triangle blue trim is represented by the blue trim

So:

$x^2 = Side\ 1^2 + Side\ 2^2$

This gives

$x^2 = 10^2 + 14^2$

$x^2 = 100 + 196$

$x^2 = 296$

Take square root

$x = \sqrt{296$

$x = 17.2in$

3 0

3 years ago

3[10-(27÷9) HELP PLEASE

steposvetlana [31]

Answer:

Step-by-step explanation:

You do the parentheses first, so 27/9 = 3

10-3 = 7

3 * 7 = 21

8 0

2 years ago

Read 2 more answers

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have

salantis [7]

Let

x--------> the number of blue beads

y--------> the number of red beads

we know that

$x+y=49$

$x=49-y$ -------> equation $1$

$x=6y$ ------> equation $2$

equate equation $1$ and equation $2$

$49-y=6y\\ 6y+y=49\\ 7y=49\\\\ y=\frac{49}{7} \\ \\ y=7$

find the value of x

$x=6*7\\ x=42$

therefore

the answer is

Ivan has $42$ $blue beads$

3 0

2 years ago

Read 2 more answers

Find b and c if <img src="https://tex.z-dn.net/?f=-x%5E2%2Bbx%2Bc" id="TexFormula1" title="-x^2+bx+c" alt="-x^2+bx+c" align="abs

larisa [96]

Answer:

Its 4.57

Step-by-step explanation:

5 0

2 years ago

In the inequality 6a+4b>10, what could be the possible value of a if b=2?

Arlecino [84]

We are given the following inequality:

$6a+4b>10$

If we replace b = 2, we get:

$\begin{gathered} 6a+4(2)>10 \\ 6a+8>10 \end{gathered}$

Now we solve for "a" first by subtracting 8 on both sides:

$\begin{gathered} 6a+8-8>10-8 \\ 6a>2 \end{gathered}$

Now we divide both sides by 6

$\frac{6a}{6}>\frac{2}{6}$

Simplifying:

$a>\frac{1}{3}$

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3

3 0

1 year ago