Answer:
185.2 g/mol.
Explanation:
Solvent = Benzene
Solute = lauryl alcohol
Given:
Mass of solute = 5 g
Mass of solvent = 0.1 kg
Freezing point of solvent, Temp.f = 4.1 °C
Initial freezing point of solvent, Temp.i = 5.5 °C
Molal freezing depression constant for Benzene, kf = 5.12 °C/m
ΔTemp.f = Temp.f - Temp.i
= 5.5 - 4.1
= 1.4 °C
ΔTemp.f = kf * m
Where m = molality
m = 1.4/5.12
= 0.27 mol/kg
Molality = number of moles of solute/mass of solvent
Number of moles = 0.27/0.1
= 0.027 mol.
Molar mass = mass/number of moles
= 5/0.027
= 185.2 g/mol.
The electron group arrangement of CH₂Cl₂ is penta-atomic. The molecular shape is tetrahedral, and the bond angle is 109.5°.
<h3>What is the bond angle?</h3>
The bond angle is the angle between the atoms of the compound. The bond angle is defined in degree. The bond length is also there. It is the distance between the nuclei of the two atoms.
The bond angle of CH₂Cl₂ is 109.5°. According to the VSEPR theory, as the structure will be tetrahedral.
Thus, the penta-atomic configuration of CH2Cl2's electrons. Tetrahedral is the molecular shape, the bond angle is 109.5°.
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Radioactivity or radioactive decay is the process that occurs when unstable isotopes or atoms release energy by emitting radiations such as ,gamma radiations, alpha radiations and beta radiations to attain stability. Therefore, in this case decay is likely to occur when a given atom has two many neutrons in its nucleus in order to attain stability.
<span>Answer: Potassium hydroxide, KOH, is considered a BASE in an acid-base reaction because it ACCEPTS a hydrogen ion from the other reactant.
According to </span><span>Brønsted–Lowry acid–base theory, Base is a specie which accepts proton (H</span>⁺) while, Acid is a specie which donate proton.
Bases may contain a negative charge or lone pair of electrons, while, Acids contain positive charge or a neutral atom with incomplete octet.
In given statement KOH is acting as a base because it contains a negatively charged hydroxyl group which can accept proton from a acid, i.e.
KOH → K⁺ + OH⁻
Reaction of OH⁻ with any acid,
K⁺ + OH⁻ + HCl → H₂O + KCl
Answer: C2H4 + 3O2 → 2CO2 + 2H2O
Explanation:
2Al + 2O2 → 2AlO + O2 Not Balanced Properly: 2Al + O2 = 2AlO
C2H4 + 3O2 → 2CO2 + 2H2O Looks Good
2CH4 + O2 → 2CO + 4H2 Not Correct: CO should be CO2
Ca + O2 → CaOH Not Balanced and No source for the H