Answer:
D. Strong nuclear force, electrostatic force, weak nuclear force, gravitational force
Answer:
mass of hydrogen collected is 0.016 gram
Explanation:
Given values:
For calculating mass we have to find the number of moles first
Ideal gas equation PV =nRT
Volume= 195 ml
Pressure: 753 torr =0.99 atm
Temperature: 25+273= 298 Kelvin
Ideal gas constant R= 0.0821 Latm/molK
Number of moles n= ?
So n= PV/RT
Adding the values
n= = (753 torr)(1 atm/760 torr)(195 mL)(1 L/1000 mL)/(0.0821 L·atm/mol·K)(273 K)
n = 0.007897 moles of H₂
Now mass of hydrogen collected = number of moles x Molar mass of H₂
= 0.007897 x 2
= 0.0157 g H₂
Now mass of hydrogen collected is 0.016 gram (rounding the amount)
Required pH = 4.93
- OH⁻ from NaOH reacts with CH₃COOH giving CH₃COO⁻ and H₂O
- Let the volume of 3.5 M NaOH be x ml
Moles of NaOH = Moles of OH⁻ = Molarity * x ml = 3.5x mmol
- The reaction table for moles is as follows:
CH₃COOH + OH⁻ → CH₃COO⁻ + H₂O
Initial 60 3.5x 40
Change -3.5x -3.5x +3.5x
Final (60-3.5x) 0 (40+3.5x)
- Substitute in Henderson equation and solve for x:
pH = pKa + log
4.93 = 4.76 + log
0.17 = log
x = 5.62 ml NaOH required
Carbon monoxide : mixture, cigarette smoke : element and ice : element ,none of them are correctly matched, therefore option 3 is correct'
Crystalline structures are created when water molecules have been organized in an ordered, cage-like form. Crystalline compounds, such as ice particles as well as water molecules, are composed of particles or molecules which are arranged in a particular order to produce an ordered component known as just a crystalline compound.
Even though it is made up of a chemical link between an atom of carbon and an atom of oxygen, carbon monoxide would be a pure material. There is only one kind of molecule that makes up carbon monoxide, when nothing is physically mixed with that as well.
carbon monoxide = pure substance
cigarette smoke = mixture
Ice = element
Hence, carbon monoxide : mixture, cigarette smoke : element and ice : element ,none of them are correctly matched, therefore option 3 is correct'
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