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tangare [24]
3 years ago
11

Can someone help me with this question please.....

Mathematics
2 answers:
viva [34]3 years ago
7 0

Answer:

9g/cm3 (g/ml)

Step-by-step explanation:

d(roe)=m/v=63g/7cm3=9g/cm3(g/ml)

d(roe)=m/v=117g/13cm3=9g/cm3(g/ml)

Lynna [10]3 years ago
4 0

Step-by-step explanation:

  • We can get the density either by converting both the masses and the volumes or we solve them like like that using the formula Density = P = Mass/Volume. After converting both mass and volume, your unit will be in kg/m^3..........Without converting, your unit will be in g/cm^3

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6/100 equals what as a decimal?
Dahasolnce [82]

Answer:

0.06  

Step-by-step explanation:

hope this helps

6 divide by 100= 0.06

3 0
3 years ago
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Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam
MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
3 years ago
Which of the following is a factor of 3x3-12x2 +X-4 ?<br> A. X+3<br> B. X+2<br> C. X-4<br> D.X-1
DiKsa [7]

Answer:

B.x+2

Step-by-step explanation:

6 0
3 years ago
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Dima020 [189]

Answer:

A. -2/7

Step-by-step explanation:

slope = rise/run = 2/(-7) = -2/7

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3 years ago
can you help me evaluate this: 7m + 14m - 6n - 5n + 2m. why do you add 6n with 5n instead of subtract?
Mademuasel [1]

Step-by-step explanation:

The reason is because it is not just 6 it is - 6 so when there are two negative numbers they don't subtract they add if it was 6n then it was to be subtracted

21m - 11n + 2m

23m - 11n

6 0
3 years ago
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