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Sunny_sXe [5.5K]
3 years ago
6

PROBLEM #1: Find the lengths of PR and QS.

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer: PR= 20

QS=20

Step-by-step explanation:

The triangles are both congruent and isosceles. 10 + 10 = 20

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Describe the domain and range of y = 2(4)x+ ³ +2.
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2 years ago
20 POINTS!!!
notka56 [123]

\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------

(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s

6 0
3 years ago
Read 2 more answers
for the following two numbers, find two factors of the first number such that their product is the first number and their sum is
zepelin [54]
You can make some algebraic equations and solve it.
The first would be:
x \times y =  - 21
The second would be
x + y =  - 4
You can then rearrange the second into
x =  - 4 - y
And subsitute it into the first like so:
( - y - 4) \times y = -  21
After that, distribute the y into the parantheses.
{ - y}^{2}  - 4y =  - 21
Subtract the 21 on both sides and multiply by -1 on both sides:
{ - y}^{2}  - 4y  +  21 \\ {y}^{2}  + 4y  -  21
You then can factor it into:
(y + 3) \times (y - 7) = 0
With Zero Product Property, we can determine y to be either -3 and 7. Since the variables are interchangable, you can say the same about x, just that whatever x is, y must be the other value.


Thus, the answer is 7 and -3.
5 0
3 years ago
Kelly earns a 7% commission on the total amount of her sales. This year, she had $210,000 in sales. How much commission did Kell
egoroff_w [7]
210,000 x .07 = 14,700 commission
4 0
3 years ago
Read 2 more answers
I need some help please
Veronika [31]
The definition of the tangent function tells you
   tan(angle) = (300 ft) / (distance to mountain)
This equation can be rearranged to
   (distance to mountain) = (300 ft) / tan(angle)

For the far end of the river,
   distance to far end = (300 ft) / tan(24°) ≈ 673.8 ft

For the near end of the river
   distance to near end = (300 ft) / tan(40°) ≈ 357.5 ft

Then the width of the river can be calculated by finding the difference of these distances:
   width of river = distance to far end - distance to near end
   width of river = 673.8 ft - 357.5 ft
   width of river = 316.3 ft

The appropriate answer choice is
   316 ft.
8 0
3 years ago
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