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DedPeter [7]
3 years ago
11

A brochure claims that the average maximum height for a certain type of plant is 0.7 m. A gardener suspects that this is not acc

urate locally due to variation in soil conditions, and believes the local height is shorter. A random sample of 40 mature plants is taken. The mean height of the sample is 0.65 m with a standard deviation of 0.20 m. Test the claim that the local mean height is less than 0.7 m using a 5% level of significance.
Mathematics
1 answer:
larisa [96]3 years ago
4 0

Answer:

As Z, it is possible to reject null hypotesis. It means that the local mean height is less tha 0.7 m with a 5% level of significance.

Step-by-step explanation:

1. Relevant data:

\mu=0.70\\N=40\\\alpha=0.05\\X=0.65\\s=0.20

2. Hypotesis testing

H_{0}=\mu=0.70

H_{1} =\mu< 0.70

3. Find the rejection area

From the one tail standard normal chart, whe have Z-value for \alpha=0.05 is 1.56

Then rejection area is left 1.56 in normal curve.

4. Find the test statistic:

Z=\frac{X-\mu_{0} }{\sigma/\sqrt{n}}

Z=\frac{0.65-0.70}{0.20/\sqrt{40}}\\Z=-1.58

5. Hypotesis Testing

Z_{\alpha}=1.56\\Z=-1.58

-1.58

As Z, it is possible to reject null hypotesis. It means that the local mean height is less tha 0.7 m with a 5% level of significance.

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