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astra-53 [7]
3 years ago
11

10 time 20 minus 5 and yeah that’s all i need

Physics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

10 \times 20 - 5 \\  \\  = 200 - 5 \\  = 195

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Finding the area of a trapezoid on a velocity versus time graph will tell you
julsineya [31]
The answer is c. velocity
6 0
3 years ago
Membrane walls of living cells have surprisingly large electric fields across them due to separation of ions. (Membranes are dis
Arturiano [62]

Answer:

Voltage, V = 0.0524 volts

Explanation:

Thickness of the membrane, d=7.95\ nm=7.95\times 10^{-9}\ m

Electric field strength, E=6.6\ MV/m=6.6\times 10^6\ V/m

We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :

V=E\times d

V=6.6\times 10^6\ V/m\times 7.95\times 10^{-9}

V = 0.0524 volts

So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.

7 0
3 years ago
The Problems: 1. Xavier starts at a position of 0 m and moves with an average speed of 0.50 m/s for 3.0 seconds. He normally mov
NemiM [27]

Answer:

(1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

Explanation:

(1). Given that,

Initial position = 0 m

Average speed = 0.50 m/s

Time = 3.0 s

We need to calculate the final position

Using formula of average speed

v_{av}=\dfrac{x_{f}+x_{i}}{t}

Where, x_{f} = final position

x_{i} = Initial position

t = total time

Put the value into the formula

0.50=\dfrac{x_{f}+0}{3.0}

x_{f}=0.50\times3.0

x_{f}=1.5\ m

(2). Given that,

Initial position = 0 m

Average speed = 0.75 m/s

Time = 4.0 s

We need to calculate the final position

Using formula of average speed

v_{av}=\dfrac{x_{f}+x_{i}}{t}

Put the value into the formula

0.75=\dfrac{x_{f}+0}{4.0}

x_{f}=0.75\times4.0

x_{f}=3\ m

(3). Given that,

Average speed = 1.25 m/s

Time = 3.0 sec

Initial position = 1.0 m

We need to calculate the final position

Using formula of average speed

v=\dfrac{x_{f}+x_{i}}{t}

Put the value into the formula

1.25=\dfrac{x_{f}+1.0}{3.0}

x_{f}=1.25\times3.0-1.0

x_{f}=2.75\ m

(4). Given that,

Average speed = 1.25 m/s

Distance = 100 m

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{100}{1.25}

t=80 sec

(5). Given that,

Average speed = 5 miles/hr

Suppose, distance = 25 miles

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{25}{5}

t=5\ hr

Hence, (1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

5 0
4 years ago
How do you find average velocity (average) from acceleration) and time (t)?
Tasya [4]

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

<u>If acceleration is constant</u>, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is <u>initially at rest</u>, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

<u>If acceleration is not constant and changes over time</u>, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

\displaystyle v(t) = v(0) + \int_0^t a(u) \, du

or if you know any other velocity for some time t₀ > 0,

\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du

8 0
3 years ago
PLEASE HELP ASAP!!!! A huge thanks to anyone who can help me with 14 problems. I'll do anything to return the favor. All true an
snow_lady [41]
Hello, I see you are in a jam. Lemme help.

1.) True
2.) True
3.) True
4.) True
5.) True

LOL these are all true ;)
4 0
3 years ago
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