1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlekseyPX
3 years ago
5

KK Company sold 10,000 Super-Spreaders on December 31, 2019, at a total price of $1,000,000, with a warranty guarantee that the

product was free of any defects. The cost of the spreaders sold is $550,000. The assurance warranties extend for a 2-year period and are estimated to cost $40,000. KK also sold extended warranties (service-type warranties) related to 2,000 spreaders for 2 years beyond the 2-year period for $12,000. Given this information, determine the amounts to report for the following at December 31, 2019: sales revenue, warranty expense, unearned warranty revenue, warranty liability, and cash
Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0

The amounts to report at December 31, 2019 are:

  • Sales revenue $1,000,000
  • Warranty expense $40,000
  • Unearned warranty revenue $12,000
  • Warranty liability $40,000
  • Cash $1,012,000

<h3>Amount to reported on income and balance sheet:</h3>

Amount reported in Income

Sales revenue                   $1,000,000

Warranty expenses           $40,000

Amount reported on the balance sheet:

Unearned service revenue      $12,000

Cash                                         $1,012,000

($1,000,000 + $12,000)  

Warranty liability                       $40,000

Inconclusion the amounts to report at December 31, 2019 are: Sales revenue $1,000,000, Warranty expense $40,000, Unearned warranty revenue $12,000, Warranty liability $40,000 and Cash $1,012,000.

Learn more about amount to report on income and balance sheet here:brainly.com/question/26103668

You might be interested in
What is the list price 45 off 1/4
Vlad1618 [11]
34 is your answer hope it helps
5 0
3 years ago
Is P(3,2) and Q(2,3)represent the same point​
nlexa [21]

Answer:no

Step-by-step explanation:

Because on a graph (2,3) means that the point is two along and three up while (3,2) means it is 3 along and two up.

6 0
3 years ago
Felicia places a rectangular rug that measures 10 feet by 11 feet in a triangular room with a base of 30 feet and height of 22 f
arsen [322]

Answer:

1. Area of rectangular rug is 110 ft^{2}

2. Area of triangular room is 330ft^{2}

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, rectangle and triangle.

step one

let us start by solving for the area of the rectangular rug

given data

Area A =  ?

Length l =  11 ft

Width w=  10 ft

we know that the area of a rectangle is expressed as

Area=Length * Width

substituting our given data we have

Area= 11*10\\Area= 110 ft^{2}

step two

let us  solve for the area of the triangular room

given data

Area A =  ?

base b =  30 ft

height  h=  22 ft

we know that the area of a triangle is expressed as

Area= \frac{1}{2} *base* height\\

substituting our given data we have

Area= \frac{1}{2} * 30* 22\\Area=\frac{660}{2} \\Area= 330 ft^{2}

8 0
3 years ago
1 The prism-shaped roof has equilateral triangular bases. Use the model you created in question #1 to calculate the height of th
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Step-by-step explanation:  As shown in the attached figure, the prism-shaped roof has equilateral triangular bases, one of which is ΔABC. We need to create an equation that models the height of one of the roof's triangular bases in terms of its sides. Let ii be AD.

See the figure attached herewith, ΔABC forms an equilateral triangle, in which AD is the height. So, D will be the mid-point of BC and ∠ADB = ∠ADC = 90°.

Now, in ΔADB, we have

AD^2=AB^2-BD^2

AD^2=AB^2-(1/2AB^2)^2

AD=√3/4AB^2

we can find the height of any one of the roof's triangular bases.

2.1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythagorean theorem, as shown in the picture, the height is √3/2a

2. if a=25 ft, then the height is  √3/2a=√3/2*25=1.732/2*25=21.7(ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l

the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*(1/2*a*√3/2a)=√3/2a^2  

so the total area of the roof is  

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.

So the total area found previously will be decreased by al

5. so the area now is √3/2a^2 + 2al  

6. now a=25 and l=2a=50

Area= √3/2a^2+2al=√3/2*25^2+2*25*50=25^2(√3/2+4)=625*4.866

=3041.3 (ft squared)

6 0
3 years ago
Brian compared the absolute values of the numbers−12,34,and−14.Arrange the numbers from least to greatest.
solniwko [45]

Answer:

-12, -14, 34

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • What is the smallest degree of rotation that will map a regular 18 gon on to itself
    15·1 answer
  • 8 cm<br> 5 cm<br> find the perimeter
    15·1 answer
  • Which statement is true about the values of X equals 1.5 and Y equals -1.5?
    8·1 answer
  • Consider that (x, y) is a solution to the system of equations. What is the product of x and y? 2x − 5y = 10 4x + 3y = 7 A) − 5 2
    11·1 answer
  • What is the answer to <br> -k - (-8k)
    11·2 answers
  • Exercise<br>1<br>Solve the inequality<br>of these equation<br>pretty please ​
    14·1 answer
  • What is the volume of the cylinder below?
    5·1 answer
  • A truck that is 10 ft. by 15 ft. by 8 ft. and carries
    5·1 answer
  • B<br> b. (2x) + +<br> )<br> (2x3/4)+1/4=
    13·1 answer
  • A 21 foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground if 14 f
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!