Answer:
The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎
Step-by-step explanation:
For a reflection across the line y = -x, we have, (x, y) → (y, x)
Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x
The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)
Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'
Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎
None of them are correct.
Answer:
A: Tax paid us $1370
B: Total cost= car cost + taxes
$27,400+ $1370
=$28,770
Step-by-step explanation:
Answer:
Train A is faster by a factor of 1.01
Step-by-step explanation:
Given:
Train A:
Distance = 175 Miles
Time = 4 Hours
Train B:
y=43.5x
To Find:
which train travels at a faster rate in by what factor =?
Solution:
The speed of the train A = 
The speed of train A =
The speed of train A = 43.75 miles per hour
Speed of the train B is the slope of the given line
The standard equation of the slope of the line is
y = mx+b
where m is the slope
and we are given with
y = 43.5x
So comparing with the standard equation
m = 43.5
Hence the speed of train B is 43.5 miles per hours
Train A travels faster
rate =1.01
0=0
5=60
10=100
15=140
17=156
33=284
I think
