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VLD [36.1K]
3 years ago
7

he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size

required to estimate the mean pulse rate of adult males. Assume that we want 90​% confidence that the sample mean is within 3 bpm of the population mean. Complete parts​ (a) through​ (c) belo
Mathematics
1 answer:
malfutka [58]3 years ago
5 0

Answer:

97

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

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The answers are option C) segment and option D) ray

<u>Step-by-step explanation</u>:

Line :

  • A line has arrow mark in the two ends. So, the diagram is not a line.

Point :

  • A point represents particular spot as a small dot. So, the diagram is not a point.

Segment :

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5 0
3 years ago
Please help ASAP!!! Christine found a sweater at Nordstrom that was priced at $72.00. She noticed there was a sign that said "Al
Olin [163]

Answer:

57.60

Step-by-step explanation:

72/100=0.72, 0.72x80=57.60

6 0
2 years ago
Please help!?!?! I'm not good with math ..
borishaifa [10]
The answer is b national baking act
7 0
3 years ago
(a+b)²= ?<br>please tell the correct answer ​
Lapatulllka [165]
A^2 + b^2 =

This is all it’s saying.
8 0
3 years ago
Read 2 more answers
Two jugs are similar. The smaller jug has radius 4cm and the bigger jug has radius
ivolga24 [154]

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}

\text{Area of smaller jug}=\dfrac{4}{9}\times 125

\text{Area of smaller jug}\approx 55.56

Therefore, the area of the smaller jug is about 55.56 cm².

6 0
2 years ago
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