First, we will use the general gas formula to get the number of moles.
PV = nRT where:
P is the pressure of gas = 751 mmHg = 100125.096375 Pascal
V is the volume = 1 liter = 0.001 m^3
n is the number of moles we want to calculate
R is the gas constant = <span>8.314 J/(K. </span>mol<span>)
T is the temperature = 31 degrees celcius = </span>304.15 degree kelvin
Substitute in the above equation to get the number of moles as follows:
100125.096375 * 0.001 = n * 8.314 * 304.15
n = 0.039595 moles
Now, we will use the number of moles to get the mass as follows:
number of moles = mass / molar mass
mass = number of moles * molar mass
number of moles = 0.039595 moles
molar mass of ammonia (NH3) = 14 + 3(1) = 17 grams
Substitute to get the mass as follows:
mass = 0.039595 * 17 = 0.673122 grams
Last step is to get the density as follows:
density = mass / volume
mass = 0.673122 grams
volume = 1 liter
density = 0.673122 / 1 = 0.673122 grams/liter = <span>0.000675 kg/L</span>
There 2.5e+6 centimeters in 25 kilometers.
Answer:
The answer to your question is below
Explanation:
1.-
a) Look for the mass number of Gold in the periodic table
Mass number = 197 g
Use proportions to answer this question
197 g of gold ------------- 6.023 x 10 ²³ atoms
4.64 g of gold ---------- x
x = (4.64 x 6.023 x 10²³) / 197
x = 1.42 x 10²² atoms
2.- mass of 4.12 x 10²⁴ molecules of glucose
Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)
= 72 + 12 + 96
= 180 g
180 g of glucose ------------------- 6.023 x 10 ²³ molecules
x ------------------- 4.12 x 10 ²⁴ molecules
x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³
x = 1231.3 g of glucose
Answer:
1034.88J
Explanation:
Given that:
mass (m) = 11.2 g, initial temperature = 0°C, final temperature = 22°C, the specific heat capacity of water (C) = 4.2 J/g°C
Temperature difference (ΔT) = final temperature - initial temperature = 22 - 0 = 22°C
The quantity of heat (Q) required to melt the ice can be calculated from the equation:
Q = mCΔT
Q = 11.2 g × 4.2 J/g°C × 22°C
Q = 1034.88J
Answer:
The right answer is "58.3%".
Explanation:
The given values are:
Mass of lithium carbonate,
= 700 mg
i.e.,
= 0.7 g
Mass of tablet,
= 1.20 g
Now,
The percentage of active ingredient will be:
= 
On substituting the given values, we get
= 
= 
= 
%
