It would be 0.780 because the 2 is not higher than a 5.
remember this saying... 5 or more add 1 more 4 or less just ignore
Given
A tea that is 22% jasmine is blended with a tea that is 13% jasmine
Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
To proof
Let us assume that the a tea that is 22% jasmine is blended = a
Let us assume that the a tea that is 13% jasmine is blended = b
Total amount of tea made = 10lb
the equation be
a + b = 10
as given
jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
write 22% in the decimal form

= 0.22
write 13% in the decimal form

= 0.13
write 19.3% in the decimal form

= 0.193
than the equation be
0.22a + 0.13b = 0.193 × 10
on simplify
22a + 13b = 193
two equation becomes
22a + 13b = 193 and a + b = 10
multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193
we get
22a - 13a + 13b -13b = 193 - 130
9a = 63
a = 7lb
put this value in the a + b = 10
we get
7 + b = 10
b = 3lb
Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .
Hence proved
Answer:
There is an error in line 2; segment BE should be a perpendicular bisector.
Step-by-step explanation:
I took the test, i got it right. :)
Answer:
For the domain indicated, the range is {-11, -7, -3, 1, 5}
Step-by-step explanation:
Given the indicated domain of f(x) you have to replace the values in the function to find the range (the "y" values of the function).
f(-2) = 5
f(0) = 1
f(2) = -3
f(4) = -7
f(6) = -11.
So the range for this domain is {-11, -7, -3, 1, 5}