Question

Answer please i dont wanna fail this test

Answer 1

Answer is C.

Explanation:

So we have 100 data, aka numbers. So the mean would be
$\dfrac{x_1 + x_2 + x_3 + \cdots + x_{100}}{100} = 267$

where bunch of x represents those data.

So then $x_1 + x_2 + \cdots + x_{100} = 267\cdot100$, right?

So we have six outliers with mean 688. That would be
$\dfrac{x_{i_1} + x_{i_2} + \cdots + x_{i_6}}6 = 688$

So then $x_{i_1} + x_{i_2} + \cdots + x_{i_6} = 688\cdot6$

Now we don't know what i₁, i₂, etc, but we can just subtract outliers from set of observations and we will know that outliers will be gone in set of observation.

So that would be
$(x_1 + \cdots + x_{100})- (x_{i_1} + \cdots + x_{i_6}) = 267\cdot100 - 688\cdot6$

Now we know that there are now 94 remaining observations. So to find mean, we just divide whole thing by 94.

$\dfrac{(x_1 + \cdots + x_{100})- (x_{i_1} + \cdots + x_{i_6})}{94} = \dfrac{267\cdot100 - 688\cdot6}{94} = \boxed{240.12766}$

Which matches C.

Hope this helps.