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pashok25 [27]
2 years ago
10

Solve the system of linear equations. 13x+y=1 2x+6y=6

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
5 0

Answer:

x = 0 and y = 1                 Solution: (0, 1)      

Step-by-step explanation:

13x +  y = 1       multiply by -6  ⇔      -78x  - 6y = -6

2x + 6y = 6     do not change  ⇔    +<u>  2x + 6y =   6    </u>

                                                           -76x  = 0

                                                                  x = 0

Use the second equation to solve for y if x = 0

2x + 6y =  6

2(0) + 6y = 6

 0 + 6y = 6

     6y = 6

       y = 1       Solution (0,1)

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Paladinen [302]

The value of x in the given equation is -\frac{4}{5}

From the question,

We are to solve the given equation

The given equation is

log_{6}(36) = 5x +6

This becomes

log_{6}(6^{2} ) = 5x +6

From one of the laws of logarithms, we have that

log_{x}(x^{2} ) = 2log_{x}(x)

and

log_{x}(x) = 1

∴ log_{6}(6^{2} ) = 5x +6 becomes

2log_{6}(6) = 5x +6

and

2(1)= 5x +6

2 = 5x +6

Now, subtract 6 from both sides

2-6 = 5x +6-6

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∴ x = -\frac{4}{5}

Hence, the value of x in the given equation is -\frac{4}{5}

Learn more on solving equations here: brainly.com/question/11802986

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