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tresset_1 [31]
3 years ago
6

The equation y = 2x + 1 is changed to y = 2x - 1. How does this change the graph of the line?

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0
Y = 2x + 1
y = 2x - 1

so the 1st one has a y int of 1 and the second one has a y int of -1...so the original line will shift down 2 units
Mademuasel [1]3 years ago
7 0

Answer:

D) The original line will shift down 2 units.

Step-by-step explanation:

The <em>rate</em><em> </em><em>of</em><em> </em><em>changes</em><em> </em>[<em>slopes</em>] remain the same [2], so all you need to do is figure out how much far \displaystyle [0, 1]is from \displaystyle [0, -1], and that would be two units:

\displaystyle -1 + 2 = 1

I am joyous to assist you anytime.

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Gemiola [76]

Answer:

X = 13

Step-by-step explanation:

7 0
2 years ago
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The sum of two numbers is 21. The larger number is 6 less than twice the smaller number. Find the two numbers.
Vesnalui [34]
Hey there! :D

21= 2x-6+x

21=3x-6

27=3x

x=9

The smaller number is 9. 

The larger number is:

9*2= 18 18-6= 12

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I hope this helps!
~kaikers
3 0
3 years ago
Is this correct please explain
uysha [10]

Answer:

79°

Step-by-step explanation:

since this figure goes around completely, the sum would be 360°

1 and 3 are equal, so you would multiply 101 by 2

101 × 2 = 202

subtract 202 from 360

360 - 202 = 158

4 and 2 are equal, so divide 158 by 2

158 ÷ 2 = 79

so angle 4 = 79°

3 0
2 years ago
A.) f(x)=3x^2-18x+27.
Alona [7]
A)
Vertex:(3,0)
x-intercepts: (3,0) 
y-intercepts: (0,27)

B)
Vertex:(0,-9)
x-intercepts:none 
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8 0
3 years ago
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An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

4 0
3 years ago
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