What percent of 208 is 197.6

Prove that triangle with side lengths of x^2-1, 2x, x^2+1 is a right triangle.

Brrunno [24]

Right triangles must follow the pythagorean theorem, so a^2+b^2=c^2.

Let's find a^2 and b^2 by squaring the first 2 side lengths.

(x^2-1)^2= x^4-2x^2+1
(2x)^2= 4x^2

Then add the two to find c^2
x^4+ 2x^2 +1= c^2

Root both sides
x^2+1=c

Since the side lengths can be plugged into the pythagorean theorem, the side lengths must represent a right triangle.
Hope this helps!

7 0

2 years ago

What is the value of this -3 2/3 ÷ 1/3

mihalych1998 [28]

Answer:

-11

Step-by-step explanation:

Convert -3 2/3 to -11/3

-11/3÷1/3

Dividing by 1/3 is the same as multipling by 3

so the equation becomes

(-11/3)(3)

=-11

8 0

3 years ago

Read 2 more answers

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

2 years ago

If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?

andreev551 [17]

Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2) / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B ) - correct

8 0

2 years ago

What is the volume of the pyramid shown?

Vilka [71]

Answer:

The answer to your question is 440 in³, this is my result I can not see the height in the picture I think the number is 40 in

Step-by-step explanation:

Data

length of a side = 6 in

height = 40 in Is really 40?

Volume of a square pyramid = ?

Process

1.- Calculate the area of the base

Ab = 6 x 6

= 36 in²

2.- Calculate the volume of the Pyramid

Volume of a square pyramid = 1/3 (36 x 40)

= 1440 / 3

= 480 in³

7 0

3 years ago