1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
USPshnik [31]
2 years ago
6

Help!!! Ill give 100 points!

Mathematics
1 answer:
shtirl [24]2 years ago
5 0

Answer:

7/20

Step-by-step explanation:

You might be interested in
A gaming console that is $300 plus 8% tax. What is the final cost of the console? (Round to nearest cent)
Novay_Z [31]

Answer:

It should be 324.

Step-by-step explanation:

7 0
3 years ago
If x=9 when y=36 and x is directly proportional to y what is x when y=6
melamori03 [73]

Answer:

.fnm k.v tkr vijt 3ogubt4er giutbgo6jgn43o4goujgnogno'itng'

Step-by-step explanation:

3 0
3 years ago
Determine whether the sequences converge.
Alik [6]
a_n=\sqrt{\dfrac{(2n-1)!}{(2n+1)!}}

Notice that

\dfrac{(2n-1)!}{(2n+1)!}=\dfrac{(2n-1)!}{(2n+1)(2n)(2n-1)!}=\dfrac1{2n(2n+1)}

So as n\to\infty you have a_n\to0. Clearly a_n must converge.

The second sequence requires a bit more work.

\begin{cases}a_1=\sqrt2\\a_n=\sqrt{2a_{n-1}}&\text{for }n\ge2\end{cases}

The monotone convergence theorem will help here; if we can show that the sequence is monotonic and bounded, then a_n will converge.

Monotonicity is often easier to establish IMO. You can do so by induction. When n=2, you have

a_2=\sqrt{2a_1}=\sqrt{2\sqrt2}=2^{3/4}>2^{1/2}=a_1

Assume a_k\ge a_{k-1}, i.e. that a_k=\sqrt{2a_{k-1}}\ge a_{k-1}. Then for n=k+1, you have

a_{k+1}=\sqrt{2a_k}=\sqrt{2\sqrt{2a_{k-1}}\ge\sqrt{2a_{k-1}}=a_k

which suggests that for all n, you have a_n\ge a_{n-1}, so the sequence is increasing monotonically.

Next, based on the fact that both a_1=\sqrt2=2^{1/2} and a_2=2^{3/4}, a reasonable guess for an upper bound may be 2. Let's convince ourselves that this is the case first by example, then by proof.

We have

a_3=\sqrt{2\times2^{3/4}}=\sqrt{2^{7/4}}=2^{7/8}
a_4=\sqrt{2\times2^{7/8}}=\sqrt{2^{15/8}}=2^{15/16}

and so on. We're getting an inkling that the explicit closed form for the sequence may be a_n=2^{(2^n-1)/2^n}, but that's not what's asked for here. At any rate, it appears reasonable that the exponent will steadily approach 1. Let's prove this.

Clearly, a_1=2^{1/2}. Let's assume this is the case for n=k, i.e. that a_k. Now for n=k+1, we have

a_{k+1}=\sqrt{2a_k}

and so by induction, it follows that a_n for all n\ge1.

Therefore the second sequence must also converge (to 2).
4 0
3 years ago
Solve this question pls. Thanks
kirill [66]

Answer:

pretty sure is it B. -1.75 and 4 but not 100% positive

3 0
2 years ago
Circle problem, please help
faust18 [17]
I think that it is A, 180..
5 0
3 years ago
Other questions:
  • Chose an equation below that represents the line passing through the point (-2,-3) with a slope of -6
    8·1 answer
  • A woman 38 years old has a daughter 14 years old. How many years ago was the woman 8 times older than the daughter?
    13·1 answer
  • Identify the domain of the function shown in the graph,
    14·1 answer
  • What is the ratio of twenty-four cans on sale at two for nine dollars?
    8·2 answers
  • The graph of the funxtion f(x)=|3x| is translated 4 units up. What is the equation of the transformed function
    14·1 answer
  • How many meters are equal to 6 kilometers? Use the pattern in the number of zeros of the product when multiplying by a power of
    6·1 answer
  • Each side of the square base is 5 inches long and the height of the pyramid is 5 inches. Approximately how much wood is in the p
    7·1 answer
  • If the measure of angle is θ is 7pi/4 , which statements are true?
    6·2 answers
  • X^2+5*x^3+7<br> Solve pls lol
    11·2 answers
  • If 2/15 is 40 then 1/15 is?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!