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brilliants [131]
3 years ago
5

Solve this question pls. Thanks

Mathematics
1 answer:
kirill [66]3 years ago
3 0

Answer:

pretty sure is it B. -1.75 and 4 but not 100% positive

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Solve for this equation:<br> x(x+3)(x+3)=0
Marta_Voda [28]

Answer:

x^3+6x^2+9x

if you are trying to find the original function

if not, and you are trying to find the zeros is

x=-3

x=0

Step-by-step explanation:

multiply x(x+3)

x^2+3x

then multiply that by x+3 and that should give you the answer

6 0
2 years ago
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Determine whether 5, 226 is divisible by 2,3,4,5,6,9, or 10.
uranmaximum [27]

Answer:

2,3,6

Step-by-step explanation:

5,226   ...(1)

unit digit=6

6 is divisible by 2,

so (1) is divisible by 2.

last two digits=26 ,not divisible by 4,

so (1) is not divisible by 4.

5+2+2+6=15 divisible by 3 but not divisible by 9.

so (1) is divisible by 3 but not divisible by 9.

2×3=6,so (1) is divisible by 6.

unit digit=6≠0 or 5

so (1) is not divisible by 5 or 10.

8 0
3 years ago
Read 2 more answers
NEED HELP ASAP, WORTH 80PTS
sp2606 [1]

D

This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)

3 0
3 years ago
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One half of the sum of a number and 10
garri49 [273]

Let's assume the number be x.

So, sum of a number and 10 can be written as x+10.

Now the given statement is "One half of the sum of a number and 10 ".

So, one half of x+10 can be written as \frac{1}{2} (x+10)

6 0
3 years ago
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
3 years ago
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