The first step of the energy usage for growth is the breakdown process. In order the animal cells can use the food, the food they eat must be broken down into smaller molecules. Step 2 is the process glycosis which converts each molecule of glucose<span> into two smaller molecules of Acetyl CoA. Step 3 is the complete oxydation of acetyl, CoA to H2O.</span>
Similar to the conversion of pyruvate to acetyl-CoA, each pyruvate molecule loses a carbon atom with the release of carbon dioxide. During the decomposition of pyruvate, electrons move to NAD + to produce NADH. It is used by cells to produce ATP.
- NADH: Three molecules are produced in the Kleb circuit
- FADH2: One molecule is produced in the Kleb circuit
- ATP or GTP: From each molecule of pyruvate during the conversion of succinyl-CoA to succinic acid Two molecules of ATP are produced. The presence of the enzyme succinyl-CoA synthetase.
Learn more about conversion of pyruvate here:brainly.com/question/4198225
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Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
Deer live in mixed forests habitats, on wooded farmlands and even in suburban areas of established cities. In winter they take to coniferous forests for shelter. Deer are a prey species, providing food for coyotes, bobcats, cougars, wolves and occasionally humans. In turn, the species helps keep vegetation in check.
The answer to this one is the first one
