The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
To figure out if the ordered pairs are a solution to the equations, you would need to plug in the points. Your points are ordered as (x,y)
You would plug in the number that's in the x spot in x, and the number in the y spot in y.
Let's start of with the first problem:
First thing you would do is plug in (-1) to x, and 6 to y.
Your equations would look like this:
6(-1) + 3(6) = 18
2(-1) + 6 = 7
What you would now do is solve the equations. When you solve them, you would get these answers
12 = 18
4 = 7
For #1, it would be no solution because the numbers do not equal each other. (Fun fact) If one of them ends up as a solution, but the other is no solution, the answer would be no solutions because BOTH of them have to be a solution to the equations given in order to be a solution.
If you do the same strategy, (plugging in the numbers to x and y), you would get the rest of the answers for the problems.
I hope this helps, if you need any more assistance, I would be glad to help!
Rewrite this as fractions:
Answer:
Step-by-step explanation:
There are an infinite number of possible solutions.
here's a few
(1 - 4i) + (-12 + 4i)
(-5.5 + 2i) + (-5.5 + i)
(-24 - 27i) + (13 + 30i)
Answer:
the answeris 276. 276+84=360.
Step-by-step explanation:
you would subtract 84 from 360 and then you have your answer!!
