Answer:
1. find the temperature in the area for longitude.
2. fine the times, and record them
Explanation:
I just took the test and the correct answer is B. eukaryotic cells
They would be conecting at the site of the injury.
The name is chemoreceptors; this is because they both respond to chemical in solution. A receptor is a protein molecule that receives chemical signals from outside a cell. When such chemical signals bind to a receptor, they cause some cellular/tissue response; e.g. a change in the electrical activity of a cell. Chemoreceptors are cells specialized to detect chemical substances and relay that information centrally in the nervous system. Chemoreceptors may monitor external stimuli, as in taste and olfaction, or internal stimuli, such as the concentrations of oxygen and carbon dioxide in the blood.
Answer:
Fructose 2,6‑bisphosphate (F26BP) activates phosphofructokinase‑1 (PFK -1) and inhibits fructose 1,6‑bisphosphatase (FBPase)
Explanation:
Fructose 2,6‑bisphosphate (F26BP) is a metabolite that is produced with an increase in glucose, hence increasing the availability of fructose-6-phosphate. With, the increased concentration of F26BP, it increases the affinity of PFK- 1 to fructose-6-phosphate, thereby activating glycolysis which enhances the catabolism of glucose. In contrast, F26BP inhibits the activity of fructose 1,6‑bisphosphatase (FBPase), hence inhibiting gluconeogenesis. Gluconeogenesis (formation of glucose) will not be need since there is the presence of glucose in the system.
In summary, fructose 2,6‑bisphosphate (F26BP) reciprocally controls the enzymatic activity of phosphofructokinase‑1 (PFK -1) and fructose 1,6‑bisphosphatase (FBPase); it inhibits gluconeogenesis by inhibiting the enzyme, FBPase and activates glycolysis by activating the enzyme PFk -1
