Answer : The heat of combustion of n-propanol is 0.554 kJ/mol
Explanation :
First we have to calculate the moles of n-propanol.
Molar mass of n-propanol = 60.09 g/mole
Now we have to calculate the heat of combustion of n-propanol.
As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ
So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)
= 0.554 kJ/mol
Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol
Answer: Pure substances cannot be separated by physical means.
Explanation:
A pure substance is a substance which contains definite composition of only one type of component. Hence, it cannot be separated by physical means.
On the other hand, a mixture is a substance which contains two or more than two types of components and they can be separated by physical means as well.
Thus, option (a) is correct one that is pure substances cannot be separated by physical means.
Answer:
-18.4°F < T(°F) < 96.8°F
Explanation:
The formula to convert Celsius to Fahrenheit is:
Replacing both temperatures in the range (-28°C and 36°C) we get:
So, the range in Fahrenheit is:
-18.4°F < T(°F) < 96.8°F
Answer:
17.92 litres.
Explanation:
1 mole of a gas occupies 22.4 litres at STP.
So 0.8 moles occupies 0.8 * 22.4
= 17.92 litres.
