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Sedbober [7]
2 years ago
11

Write a balanced half-reaction for the oxidation of gaseous nitric oxide NO to nitrate ion NO−3 in acidic aqueous solution. Be s

ure to add physical state symbols where appropriate.
Chemistry
1 answer:
crimeas [40]2 years ago
3 0

Answer:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the initial version of the half-reaction as follows:

NO\rightarrow NO_3^-

Now, we assign the oxidation numbers to both nitrogen atoms:

N^{2+}O\rightarrow N^{5+}O_3^-

It means three electrons are carried, two water molecules are needed on the left side in order to balance the oxygen atoms and consequently four hydronium ions to balance hydrogen atoms in acidic media:

2H_2O(l)+NO(g)\rightarrow NO_3^-(aq) +4H^+(aq)+3e^-

Regards!

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match these items. three-dimensional bonding, hardest natural substance, used as lubricant, nonconductor, weak planar bonds, car
DENIUS [597]

Answer:

1. three-dimensional bonding

Diamond

2. Hardest natural substance

diamond

3. Used as lubricant

Graphite

4. nonconductor

Diamond

5. Weak, planar bonds

Graphite

6.Carbon black or soot

Amorphous

Explanation;

sorry im late, hopefully this can help somebody :)

4 0
2 years ago
Which choice below would match homozygous recessive?
LUCKY_DIMON [66]
The answer is B

Homozygous mean the same and you know that the two alleles will be the same (either BB or bb) and receive is usually the lower case set of alleles
8 0
2 years ago
Read 2 more answers
Where are human cells located (in living organisms)
defon
All inside and out in the human body
3 0
3 years ago
Using your knowledge of symbols, determine which compound listed must contain both copper and oxygen.
Colt1911 [192]

Answer:

Malachite

Explanation:

Malachite is the only listed compound that must contain copper and oxygen.

Copper and oxygen are both elements found on the periodic table. They have the following symbols;

         Copper  = Cu

         Oxygen  = O

From the given choices, only option 1 has the symbol Cu and O.

So only malachite contains both copper and oxygen.

4 0
2 years ago
What quantity of energy, in joules, is required to raise the temperature of 425 g of tin from room temperature, 25.0 °C, to its
Rama09 [41]

Answer:

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is 45.249 kiloJoules.

Explanation:

Mass of the tin ,m= 425 g

Heat capacity of the tin ,c= 0.227 J/g K

Initial temperature of the tin ,T_1= 25.0 °C = 298.15 K

Final temperature of the tin, T_2= 231.9 °C = 505.05 K

Let the heat required to change the temperature of tin from 298.15 K to 505.05 K be Q.

Q=mc\times (T_2-T_1)

=425 g\times 0.227 J/g K\times (505.05K - 298.15 K)=19,960.68 J=19.961 kJ

Heat required to melt tin at 505.05 K be Q'

The heat of fusion of tin metal =\Delta H_{fus}=59.2 J/g

Q'= m\times \Delta H_{fus}=425 g\times 59.2 J/g=25,287.5 J=25.288 kJ

Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is:

= Q+Q' =  19.961 kJ + 25.288 kJ = 45.249 kJ

6 0
3 years ago
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