Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
Answer: 3M
Explanation: Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
where,
n = moles of solute 
= 0.6 moles
= volume of solution in ml= 200 ml
Now put all the given values in the formula of molarity, we get
Therefore, the molarity of solution will be 3M.
Atoms have an overall charge of zero because the charge of the electron is canceled by a proton and a neutron has a net charge of 0.If you were to take out an electron,you will create an ion(ion is an atom with a charge).This ion will have a charge because it now has different amount of electrons and protons.
Source:<span>webcast.berkeley.edu
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Answer:
3.861x10⁻⁹ mol Pb⁺²
Explanation:
We can <u>define ppm as mg of Pb²⁺ per liter of water</u>.
We<u> calculate the mass of lead ion in 100 mL of water</u>:
- 100.0 mL ⇒ 100.0 / 1000 = 0.100 L
- 0.100 L * 0.0080 ppm = 8x10⁻⁴ mg Pb⁺²
Now we <u>convert mass of lead to moles</u>, using its molar mass:
- 8x10⁻⁴ mg ⇒ 8x10⁻⁴ / 1000 = 8x10⁻⁷ g
- 8x10⁻⁷ g Pb²⁺ ÷ 207.2 g/mol = 3.861x10⁻⁹ mol Pb⁺²
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
A. Both have the same molar mass.
B. Both have the same number of ions.
C. Both are made up of 6.02 mc014-1 1023 molecules.
D. Both are made up of 6.02 mc014-2 1023 formula units.
The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D
