Find the value of x in the triangle shown below.

Can you guys help? Need to find x, BA, DA

7nadin3 [17]

Answer:

x=2,BA=DA which is7

Step-by-step explanation:

5x-3=3x+1

both sides share an angle and B=D right angles

5x-3x=1+3

2x=4

x=4÷2

x=2

BA=5x-3

BA=5(2)-3

BA=10-3

BA=7

DA=3x+1

DA=3(2)+1

DA=6+1

DA=7

4 0

3 years ago

Solve. 3(x + 1) - 2x = -6 * x = 1 x = 5 x = -7 x = -9

Vadim26 [7]

The answer is x=9 because if you do 3x+-2 that gives you 1 and 1 divided by 9 is 9 and you get that by getting rid of your 6 first and adding it to the 3 from 3(x+1)

7 0

3 years ago

Use Stokes' Theorem to calculate the circulation of the field F around the curve C in the indicated direction. F = 3yi + yj+zk

jok3333 [9.3K]

Answer:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$ = 12π

Step-by-step explanation:

The field F is given by:

$F = 3y\hat{i} + y\hat{j}+z\hat{k}$ (1)

The curve C is the ellipse:

$\frac{x^2}{4}+\frac{y^2}{64}=1\\\\(\frac{x}{2})^2+(\frac{y}{8})^2=1$

In order to calculate the circulation of F around the curve C, you first find the parametric equation for the given ellipse.

The general form of an ellipse equation is:

$(\frac{x}{a})^2+(\frac{y}{b})^2=1$

The parametric equation is:

$r(t)=acost \hat{i} + bsint\hat{j}=2cost\hat{i}+8sint\hat{j}$ (2)

The Stokes's theorem is given by the following identity:

$\int \int \bigtriangledown F\ X\ dS = \int F\cdot dr$

The path integral is also:

$\int F\cdot dr=\int F(r(t))\cdot dr(t)$ (3)

For F(r(t)) and dr(t) you obtain:

$F(r(t))=3(8sint)\hat{j}+(8sint)\hat{j}+(z)\hat{k}\\\\dr(t)=(-2sint\hat{i}+8cost\hat{j}+0\hat{k})dt\\\\F(r(t))\cdot dr(t)=(-48sin^2t+64cos^2t)dt$

Next, in the equation (3) you obtain:

$\int_0^{2\pi} (-48sin^2t+64cos^2t)dt=\int_0^{2\pi}(-\frac{48}{2}(1-cos2t)+\frac{64}{2}(1+cos2t))dt\\\\=\int_0^{2\pi}(-24+24cos2t+32+32cos2t)dt\\\\=\int_0^{2\pi}(6+56cos2t)dt\\\\=[6t+56sin2t]_0^{2\pi}=[6(2\pi)-0]=12\pi$

The circulation of the field around C is 12π

5 0

3 years ago

On Thursday, the amount of snowfall was 1/8 cm. On Wednesday, the amount of snowfall was 4 1/4 cm. What was the amount of snowfa

marysya [2.9K]

The total amount of snowfall on the two days combined is 4 3/8 cm

<h3>Addition of fractions </h3>

From the question, we are to determine the amount of snowfall on the two days combined

From the given information,

the amount of snowfall was 1/8 cm on Thursday

The amount of snowfall was 4 1/4 cm on Wednesday

Then,

The total amount of snowfall on the two days combined will be

$\frac{1}{8}+4\frac{1}{4}$ cm

= $\frac{1}{8}+\frac{17}{4}$

= $\frac{1+34}{8}$

= $\frac{35}{8}$

= $4\frac{3}{8} \ cm$

Hence, the total amount of snowfall on the two days combined is 4 3/8 cm

Learn more on Addition of fractions here: brainly.com/question/78672

#SPJ1

8 0

2 years ago

Find the area of the shaded sector. Enter your answer as a number, rounded to the nearest tenth (no units). shaded value 243 deg

Makovka662 [10]

Shaded area will be the part of the area of the circle which have a central angel = 243

Shaded area = (243/360) π r^2
= (243/360) * 3.14 * 12.5^2
= 331.2

8 0

4 years ago

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