Im not entirely sure what the scale factor is, but i do know that 10 ft is 20 times bigger than 6in, 4 cm is 16 times bigger than 2.5mm, and that 15 yards is 9times bigger than 5ft. If that helps at all
Answer:
Step-by-step explanation:
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The top base is : 14mm
The bottom base is: 36mm
The height is: 15mm
First you need to add the top and bottom bases together and divide it by 2
(14mm + 36mm) / 2
= 50mm/2
=25mm
Then you need to times it by the height
25mm x 15mm = 375mm^2
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.
Similarly, we have
Now, to find the lengths of the diagonals,
So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
-16/3 =x
Step-by-step explanation:
3(x-2)+4x=10(x+1)
Distribute
3x -6 +4x = 10x +10
Combine like terms
7x -6 = 10x+10
Subtract 7x from each side
7x-6-7x = 10x-7x +10
-6 = 3x+10
Subtract 10 from each side
-6-10 = 3x+10-10
-16 = 3x
Divide by 3
-16/3 = 3x/3
-16/3 =x